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irina1246 [14]
2 years ago
14

Besties help please,,,,,,,,

Mathematics
1 answer:
Leno4ka [110]2 years ago
5 0

Answer:

Range: -5<y<3   [-5,3]

Domain: -3<x<5 [-3,5]

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(7+5 + 4 . 13 - 2 <br><br> Please simplify this expression with all steps thank you
FinnZ [79.3K]

Answer:

We apply the BODMAS rule

(7+5+4).(13-2)

(16).(11)

=176

Hope was useful

6 0
2 years ago
Read 2 more answers
I need help with this asap!!!! ​
Yuri [45]

Answer:

26.6 but that is not one of yor answers...

I think you have a typo in "A"

I think that your have a typo in the answers

x/sin(40) = 32/sin(90)

x = 26.6

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
In a popular online role playing game, players can create detailed designs for theircharacter's "costumes," or appearance. Juan
Virty [35]
P\approx0.90

1) The first thing we need to do is to find the total number of visitors. This is going to be our Sample Space

31+26+2=31+28=59 Visitors altogether

2) The next thing to do is to find the favorable event. Note that we can see that 26 people purchased only one costume.

3) The final and last step is to find the probability, so we can write out the following:

P=\frac{26}{59}=0.8965\approx0.90

Thus, this is the answer: 0.90

4 0
1 year ago
Help me pleaseee I need help
MAVERICK [17]
I think it is b because probability of 2 is 1/6 then probability of 4 is 1/6. If you times them together 1/6x1/6 it will equal 1/36 so b
6 0
2 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
2 years ago
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