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2 years ago

Besties help please,,,,,,,,

Mathematics

1 answer:

Leno4ka [110]2 years ago

5 0

Answer:

Range: -5<y<3 [-5,3]

Domain: -3<x<5 [-3,5]

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25. Willa purchases a vase for her kitchen

IgorC [24]

Answer:

7,7, and 7

Step-by-step explanation:

If she vase is cubical we know that all 3 dimensions are the same. This means that x^3 = 343. So we know the answer is the cube root of 343, which is 7

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3 years ago

3(2x - 1) + 7 = -44 solve for x

Jet001 [13]

Answer:

I love algebra anyways

The ans is in the picture with the steps how i got it

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Step-by-step explanation:

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3 years ago

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X+ 2 / X + 3 =5 plz give me and<br><br><br><br>

Anna35 [415]

Answer:

The answer is x = -13/4

Step-by-step explanation:

-13/4 + 2 / -13/4 +3 = 5

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2 years ago

The coordinates R(1, -3), S(3, -1) T(5,-7) form what type of polygon?

Reika [66]

- It's an obtuse triangle.

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3 years ago

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More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh

Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = $\int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx$

= $\int_{-1.34}^{1.34}(5x^{2}-9)dx$

= $[\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}$

= $[\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]$

= $[-4.01+12.06-4.01+12.06]$

= 16.1 unit²

6 0

3 years ago