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Eva8 [605]
3 years ago
15

Can someone help me out with this?

Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0

9514 1404 393

Answer:

  the solution set will be non-empty

Step-by-step explanation:

The original inequalities describe regions bounded by parallel lines. The solution is the intersection of the region above the upper line and below the lower line. There is no intersection of those regions, so there is no solution to the original inequalities.

__

When the inequality symbols are reversed, the solution region is the intersection of the region below the upper line and above the lower line. That is, the solution region now exists and is the space between the lines (not including the lines themselves). A graph of this new solution region is attached.

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Someone help plss show work​
Mazyrski [523]

Answer:

Slope: \frac{3}{5}

Y-Intercept: (0,-5)

Step-by-step explanation:

1. To find the slope, we need to have the equation in slope-intercept form, which is y=mx+b. In this case, our equation is already in this form. m is what your slope is. In this case, our

2. To find the y-intercept we look at value b that is in y=mx+b. In this case, b is -5. So, our ordered pair is (0,-5).

4 0
3 years ago
Read 2 more answers
A 12 foot ladder is leaning against the side of a building. The top of the ladder reaches 10 feet up the side of the building. A
Soloha48 [4]
√135=3√15.....................

5 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
A coffee pot holds 3 1/4 quarts of coffee. How much is this in cups? Write your answer as a whole number or a mixed number in si
Rina8888 [55]

Answer:

13 cup i hope this help

Step-by-step explanation:

4 0
3 years ago
In the graph shown, at what value of x does the value of y change from increasing to decreasing or decreasing to increasing?
kotykmax [81]

Answer:

Your original answer is corrrect

Step-by-step explanation:

At X= -1, Y decreases and then it rises back to -1 and continues to increase

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