Answer: x < -12
Step-by-step explanation:
When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of <u>
pemdas</u>
and to make sure that we take each step carefully.
We first would <u>
</u>
<u>
(first)</u>
simplify the following:
the next term is 1 because 64 divide by 16 is 4 which means the geometric sequence is decreasing by 4
Answer:
Step-by-step explanation:
Given the first two numbers of a sequence as 2, 6...
If it is an arithmetic difference, the common difference will be d = 6-2 = 4
Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d
a is the first term = 2
d is the common difference = 4
n is the number if terms
Substituting the given values in the formula.
Nth term Tn = 2+(n-1)4
Tn = 2+4n-4
Tn = 4n-4+2
Tn = 4n-2
2) If the sequence us a geometric sequence
Nth term of the sequence Tn = ar^(n-1)
r is the common ratio
r is gotten by the ratio of the terms I.e
r = T2/T1
r = 6/2
r = 3
Since a = 2
Tn = 2(3)^(n-1)
Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)
The answer to the question
