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Pavlova-9 [17]
3 years ago
12

4x-2+4=4x-1-1 Please help!

Mathematics
1 answer:
Vladimir [108]3 years ago
4 0

Answer:

There are no solutions

Step-by-step explanation:

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kompoz [17]

Answer:

There are no solutions

Step-by-step explanation:

Because the lines are parallel, they will never meet, meaning there are no solutions to this system of equations

7 0
3 years ago
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docker41 [41]

let's firstly, convert the mixed fraction to improper fraction, and then subtract.


\bf \stackrel{mixed}{2\frac{3}{4}}\implies \cfrac{2\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{11}{4}}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\cfrac{11}{4}-\cfrac{2}{3}\implies \stackrel{\textit{our LCD will be 12}}{\cfrac{(3)11-(4)2}{12}}\implies \cfrac{33-8}{12}\implies \cfrac{25}{12}\implies 2\frac{1}{12}

8 0
3 years ago
Rewrite each statement using the appropriate mathematical language 1. There exists a number b belonging to the set B 2. Even num
Shtirlitz [24]

Answer:

1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻

Step-by-step explanation:

1. Let b be the number and B be the set, so mathematically, it is written as

b ∈ B.

2. Let  a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write

∀ a ∈ N; 2a ∈ Z

3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.

Since each set is a subset of the latter set, we write

N ⊂ Z ⊂ Q ⊂ R .

4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write

J ≤ J⁻¹ : J ∈ Z⁻

4 0
3 years ago
Help me. Please due today
Schach [20]

Answer:

2). As x-> -∞, f(x)->∞

    As x-> ∞, f(x)-> -∞

5). As x-> -∞, f(x)-> -∞

    As x-> ∞, f(x)-> ∞

3). As x-> -∞, f(x)-> -∞

    As x-> ∞, f(x)-> ∞

6). As x-> -∞, f(x)-> ∞

    As x-> ∞, f(x)-> ∞

Step-by-step explanation:

I just watched a quick video so you can't completely trust me, but i tried my best. Hopefully someone more trustworthy for this comes in.

6 0
3 years ago
The base of an isosceles right triangle is 30 cm. What is its area?
dlinn [17]

Answer:

A = 450 cm²

Step-by-step explanation:

Since the right triangle is isosceles then the 2 logs are congruent , both 30 cm and at right angles to each other.

The area (A ) of the triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Here b = h = 30 , then

A = \frac{1}{2} × 30 × 30 = \frac{1}{2} × 900 = 450 cm²

7 0
3 years ago
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