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UkoKoshka [18]
3 years ago
13

Use the graph of the line shown.

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

that is the answer to letter A y=3/10+3

That is the answer to letter B 3

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If we assume the club membership includes

\bullet\ \mbox{6 junior boys}\\ \bullet\ \mbox{8 junior girls}\\ \bullet\ \mbox{16 senior boys}\\ \bullet\ \mbox{12 senior girls}

then the blanks in the Juniors circle must be filled in with 6 and 8 (with the 8 going in the overlap with girls). The remaining blank in the Girls circle must be filled in with 12, the number of senior girls. The blank outside both circles is the number of senior boys (members who are not juniors and not girls), 16.

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The answer to the question is the second option.

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How do we derive the sum rule in differentiation? (ie. (u+v)' = u' + v')
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It follows from the definition of the derivative and basic properties of arithmetic. Let <em>f(x)</em> and <em>g(x)</em> be functions. Their derivatives, if the following limits exist, are

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h\text{ and }g'(x)\lim_{h\to0}\frac{g(x+h)-g(x)}h

The derivative of <em>f(x)</em> + <em>g(x)</em> is then

\displaystyle \big(f(x)+g(x)\big)' = \lim_{h\to0}\big(f(x)+g(x)\big) \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{\big(f(x+h)+g(x+h)\big)-\big(f(x)+g(x)\big)}h \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{\big(f(x+h)-f(x)\big)+\big(g(x+h)-g(x)\big)}h \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{f(x+h)-f(x)}h+\lim_{h\to0}\frac{g(x+h)-g(x)}h \\\\ \big(f(x)+g(x)\big)' = f'(x) + g'(x)

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2 years ago
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