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GarryVolchara [31]
3 years ago
9

Show how you can solve this proportion using both the cross‐product property and the reciprocal property.

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Answer:95

Step-by-step explanation:2x19=38

5x19=95

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Length = 12 yardsWidth = 6 yards.
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3 years ago
If ∠TUV = 3x+15 and ∠MRS = 20x+4 are supplements of each other, identify the measure of the larger angle.
zzz [600]

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Step-by-step explanation:it’s 3 thank me

4 0
3 years ago
The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0
STatiana [176]

Answer:

The marginal-revenue equation is R'(x)=0.1226x+1.1584.

The marginal revenue for the production of 200,000,000 bushels is R'(x)=1.4036.

The marginal revenue for the production of 650,000,000 bushels is R'(x)=9.1274.

Step-by-step explanation:

The derivative R'(x) of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

We know the revenue function, R(x) = 0.0613x^{2} +1.1584x+2.4813. Therefore, the marginal revenue function is

R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584

To find the marginal revenue for the production of:

200,000,000 bushels we use x = 2, since x is in units of hundreds of million of dollars.

R'(x)=0.1226\cdot \:2+1.1584\\\\R'(x)=0.2452+1.1584\\\\R'(x)=1.4036

650,000,000 bushels we use x = 65, since x is in units of hundreds of million of dollars.

R'(x)=0.1226\cdot \:65+1.1584\\\\R'(x)=7.969+1.1584\\\\R'(x)=9.1274

3 0
3 years ago
When working with integers, when do you add?
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Answer: Ello mate, this image I provided below should help you out, let me know if you need anything else.

Step-by-step explanation:

5 0
3 years ago
25 Trent's watch runs at half the speed itshould. In other words, the hands on thewatch move only a half hour when an hourof tim
sergeinik [125]

Given that Trent's watch runs at half the speed it should run, this implies that

for every hour passed, his watch moves by half an hour.

Hence, for every half-hour passed, Trent's watch moves by 15 minutes.

Hence, when the real time is 10:30 am, Trent's watch will show 9:15 am.

6 0
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