<h3>
Answer: 34%</h3>
This result is approximate.
=========================================================
Explanation:
mu = 750 = mean
sigma = 75 = standard deviation
The raw scores or x values are x = 750 and x = 825
Let's compute the z score for each x value
z = (x - mu)/sigma
z = (750 - 750)/75
z = 0
and
z = (x - mu)/sigma
z = (825 - 750)/75
z = 1
Therefore P(750 ≤ x ≤ 825) is equivalent to P(0 ≤ z ≤ 1) in this context.
Use a z score table to determine that
P(z ≤ 0) = 0.5
P(z ≤ 1) = 0.84314 approximately
So,
P(a ≤ z ≤ b) = P(z ≤ b) - P(z ≤ a)
P(0 ≤ z ≤ 1) = P(z ≤ 1) - P(z ≤ 0)
P(0 ≤ z ≤ 1) = 0.84314 - 0.5
P(0 ≤ z ≤ 1) = 0.34314 approximately
The value 0.34314 then converts to 34.314% which rounds to <u>34%</u>
Or you could use the empirical rule as shown below. The pink section on the right is marked <u>34%</u> which is approximate. This pink section is between z = 0 and z = 1.
Answer:
15
Step-by-step explanation:
Answer:
<h3>By 161700 ways this test batch can be chosen.</h3>
Step-by-step explanation:
We are given that total number of bulbs are = 100.
Number of bulbs are tested = 3.
Please note, when order it not important, we apply combination.
Choosing 3 bulbs out of 100 don't need any specific order.
Therefore, applying combination formula for choosing 3 bulbs out of 100 bulbs.
read as r out of n.
Plugging n=100 and r=3 in above formula, we get
Expanding 100! upto 97!, we get
=
Crossing out common 97! from top and bottom, we get
=
Expanding 3!, we get
=
= 100 × 33 × 49
= 161700 ways.
<h3>Therefore, by 161700 ways this test batch can be chosen.</h3>
Answer:
C
Step-by-step explanation:
An equation is where you already have the answer but you have to find out what the variable is to prove that the equation is true.
Answer:
9
Step-by-step explanation:
18 ÷ 6 × [1] + 6
18 ÷ 6 + 6
3 + 6
9
