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FinnZ [79.3K]
2 years ago
8

Solve the following:

Mathematics
1 answer:
olga_2 [115]2 years ago
5 0

Answer:

Do in calculator simple answer

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Laboratory tests show that the lives of
SIZIF [17.4K]
<h3>Answer:  34%</h3>

This result is approximate.

=========================================================

Explanation:

mu = 750 = mean

sigma = 75 = standard deviation

The raw scores or x values are x = 750 and x = 825

Let's compute the z score for each x value

z = (x - mu)/sigma

z = (750 - 750)/75

z = 0

and

z = (x - mu)/sigma

z = (825 - 750)/75

z = 1

Therefore P(750 ≤ x ≤ 825) is equivalent to P(0 ≤ z ≤ 1) in this context.

Use a z score table to determine that

P(z ≤ 0) = 0.5

P(z ≤ 1) = 0.84314 approximately

So,

P(a ≤ z ≤ b) = P(z ≤ b) - P(z ≤ a)

P(0 ≤ z ≤ 1) = P(z ≤ 1) - P(z ≤ 0)

P(0 ≤ z ≤ 1) = 0.84314 - 0.5

P(0 ≤ z ≤ 1) = 0.34314 approximately

The value 0.34314 then converts to 34.314% which rounds to <u>34%</u>

Or you could use the empirical rule as shown below. The pink section on the right is marked <u>34%</u> which is approximate. This pink section is between z = 0 and z = 1.

6 0
2 years ago
Given 4s+3-8t when s=7 and t=2.
yaroslaw [1]

Answer:

15

Step-by-step explanation:

4x+3-8t\\\\s=7\\\\t=2\\\\4(7)+3-8(2)\\\\28+3-16\\\\28-13\\\\15

3 0
3 years ago
As part of quality-control program, 3 light bulbs from each bath of 100 are tested. In how many ways can this test batch be chos
hichkok12 [17]

Answer:

<h3>By 161700 ways this test batch can be chosen.</h3>

Step-by-step explanation:

We are given that total number of bulbs are = 100.

Number of bulbs are tested = 3.

Please note, when order it not important, we apply combination.

Choosing 3 bulbs out of 100 don't need any specific order.

Therefore, applying combination formula for choosing 3 bulbs out of 100 bulbs.

^nCr = \frac{n!}{(n-r)!r!} read as r out of n.

Plugging n=100 and r=3 in above formula, we get

^100C3 = \frac{100!}{(100-3)!3!}

Expanding 100! upto 97!, we get

=\frac{100\times 99\times 98\times 97!}{97!3!}

Crossing out common 97! from top and bottom, we get

=\frac{100\times 99\times 98}{3!}

Expanding 3!, we get

=\frac{100\times 99\times 98}{3\times 2\times 1}

= 100 × 33  × 49

= 161700 ways.

<h3>Therefore,  by 161700 ways this test batch can be chosen.</h3>
3 0
3 years ago
Which of the following is an EQUATION?
Artist 52 [7]

Answer:

C

Step-by-step explanation:

An equation is where you already have the answer but you have to find out what the variable is to prove that the equation is true.

8 0
3 years ago
Read 2 more answers
18 ÷ 6 × [4 - 3] + 6
shepuryov [24]

Answer:

9

Step-by-step explanation:

18 ÷ 6 × [1] + 6

18 ÷ 6 + 6

3 + 6

9

6 0
2 years ago
Read 2 more answers
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