Solve the following:

No links I need the full answer to the perimeter of the trapezoid below

viktelen [127]

Answer:

26

Step-by-step explanation:

All you have to do is add up all the sides and lengths of the rectangle. 7+6+5+8=26

3 0

3 years ago

Read 2 more answers

A parallelogram has an area of x2+ 9x− 36.

Serhud [2]

Answer:

a) Length $x + 12$ , Width $x - 3$ , b) $x = 3$

Step-by-step explanation:

a) The expressions for the length and width of the parallelogram can be determined by factorizing the polynomial:

$A = x^{2} + 9\cdot x - 36$

$A = (x+12)\cdot (x-3)$

Length

$x + 12$

Width

$x - 3$

b) Since area is a positive variable, the set of solutions encompass all values of x such that area is zero o greater. Then, there are two interval where A is positive:

- When both binomials are negative.

$x \leq 3$ and $x \leq -12$

$x \leq -12$

- When both binomials are positive.

$x \geq 3$ and $x \geq -12$

$x \geq 3$

Since x is an integer, x must be positive and therefore the least possible value of x is:

$x = 3$

6 0

4 years ago

For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10

professor190 [17]

The true statements are:

Tyson's expression is not equivalent to the original expression
The equivalent expression is: $\frac{1}{2}g- \frac 1{5}$

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}$

Collect like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10} -\frac{1}{10}$

Evaluate the like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}$

Tyler's equivalent expression is given as:

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}$

Collect like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}$

Evaluate the like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g$

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0

2 years ago

14.<br> 106<br> 102<br> 103<br> what is the total?

Over [174]

Answer:

325

Step-by-step explanation:

You have to add them all up. (14+106+102+103)

6 0

3 years ago

Read 2 more answers

A pail contained 3.68L of water more than a bottle. After Bill poured away 1.2L of water from the pail, the pail contained 3 tim

julsineya [31]

For the sake of simplicity, let us say that the bottle contains x liters of water.

The pail originally contained x+3.68 L of water
After pouring out 1.2L, the pail contains x+(3.68-1.2)L or x+2.48 L
<span>
(a) How much more water did the pail contain than the bottle in the end?
Since the bottle contains x L of water, the pail (containing x+2.48 L of water) contains (x+2.48) - x more liters of water than the bottle or "the pail contained 2.48 L of water more than the bottle"

</span><span>(b) How much water did the bottle contain?
</span>We are told that after pouring the 1.2L of water out, the pail contained 3 times as much water as the pail. Therefore, 3x = x+2.48. Subtracting x from both sides gives us 2x = 2.48. Dividing both sides by 2 gives us x = 1.24L

7 0

3 years ago