Remark
The slope intercept form is
y = mx + b
Note that the y has 1 as its coefficient and b is related to the 11 (which is neither an x or y term)
Solution
Subtract 2x from both sides.
2x - 2x - 5y = 11 - 2x Combine like terms
-5y = 11 - 2x Divide by - 5
-5y/-5 = 11/-5 - 2x/-5 Do the division
y = -11/5 + 2x / 5 Answer
Discussion
This is not the only answer
It could be
y = 0.4x - 2.2
If you have answers please list them
9514 1404 393
Answer:
J p = 8t +12
Step-by-step explanation:
You can see that the p-values have differences of 8, while the t values have differences of 1. That means the "rate of change" is 8/1 = 8. This will be the coefficient of t in the equation you're looking for.
Only one answer choice has 8t as part of the equation:
p = 8t +12
______
<em>Additional comment</em>
If you decide to try the values of t in the offered choices, it often works to start with the second value of t. The answer choices are sometimes tailored to match for the first value in the table. Usually the second value of t will quickly identify the correct one.
For t=2, ...
F: p = 20·2 = 40 ≠ 28
G: p = 11·2 = 22 ≠ 28
H: p = 20·2 +12 = 52 ≠ 28
J: p = 8·2 +12 = 28 . . . . the correct choice
Answer:
f(g))(0) = 0
Step-by-step explanation:
assuming you mean f(g)(0)
evaluate g(0) then substitute the value obtained into f
x = 0 then g(0) = 2 ← from graph (0, 2 ) , then
x = 2 then f(2) = 0 ← from graph (2, 0 )
Thanks for the question!
Don't forget 0 is a whole number:
0 + 12
1 + 11
2 + 10
3 + 9
4 + 8
5 + 7
6 + 6
Hope this helps!
Answer:
The average acceleration of train is 
Step-by-step explanation:
We have,
A train that slows down from 15 m/s to 8.6 m/s in 1.2 s. It means that 15 m/s is its initial velocity and 8.6 m/s is its final velocity.
It is required to find the average acceleration of the train.
The average acceleration of train is . Negative signs shows that the train is decelerating.
