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3 years ago

11

The APR of Kylee's savings account is 5.6% and the interest is compounded quarterly. If the principal in Kylee's savings account

is $5800 for an entire year, what will be the balance of her account after all the interest is paid?

1 answer:

yuradex [85]3 years ago

4 0

A=5,800×(1+0.056÷4)^(4×1)
=6,131.68

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Help if you answer I’ll mark you brainliest

Delicious77 [7]

Answer:

I CAN'T SEE ANYTHING FROM THAT FAR SORRY BUT I WISH I COULD HELP YOU!!!

Step-by-step explanation:

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3 years ago

Read 2 more answers

Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. (If an answer d

andrey2020 [161]

Answer:

The maximum value is 1/27 and the minimum value is 0.

Step-by-step explanation:

Note that the given function is equal to $(xyz)^2$ then it means that it is positive i.e $f(x,y,z)\geq 0$ .

Consider the function $F(x,y,z,\lambda)=x^2y^2z^2-\lambda (x^2+y^2+z^2-1)$

We want that the gradient of this function is equal to zero. That is (the calculations in between are omitted)

$\frac{\partial F}{\partial x} = 2x(y^2z^2 - \lambda)=0$

$\frac{\partial F}{\partial y} = 2y(x^2z^2 - \lambda)=0$

$\frac{\partial F}{\partial z} = 2z(x^2y^2 - \lambda)=0$

$\frac{\partial F}{\partial \lambda} = (x^2+y^2+z^2-1)=0$

Note that the last equation is our restriction. The restriction guarantees us that at least one of the variables is non-zero. We've got 3 options, either 1, 2 or none of them are zero.

If any of them is zero, we have that the value of the original function is 0. We just need to check that there exists a value for lambda.

Suppose that x is zero. Then, from the second and third equation we have that

$-2y\lambda = -2z\lambda$ . If lambda is not zero, then y =z. But, since $-2y\lambda=0$ and lambda is not zero, this implies that x=y=z=0 which is not possible. This proofs that if one of the variables is 0, then lambda is zero. So, having one or two variables equal to zero are feasible solutions for the problem.

Suppose that only x is zero, then we have the solution set $y^2+z^2=1$ .

If both x,y are zero, then we have the solution set $z^2=1$ . We can find the different solution sets by choosing the variables that are set to zero.

NOw, suppose that none of the variables are zero.

From the first and second equation we have that

$\lambda = y^2z^2 = x^2z^2$ which implies $x^2=y^2$

Also, from the first and third equation we have that

$\lambda = y^2z^2 = x^2y^2$ which implies $x^2=z^2$

So, in this case, replacing this in the restriction we have $3z^2=1$ , which gives as another solution set. On this set, we have $x^2=y^2=z^2=\frac{1}{3}$ . Over this solution set, we have that the value of our function is $\frac{1}{3^3}= \frac{1}{27}$

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3 years ago

Is it possible to build a triangle with inside angles of 90 degrees , 50 degrees, and 60 degrees?

N76 [4]

Answer:

No

Step-by-step explanation:

Given: Angles of a triangle are equal to 90 degrees , 50 degrees, and 60 degrees

To check : if it possible to build a triangle with given angles

Solution:

According to angle sum property of a triangle, sum of angles of a triangle is equal to $180^{\circ}$

Here,

sum of given angles = $90^{\circ}+50^{\circ}+60^{\circ}=200^{\circ}\neq 180^{\circ}$

Therefore, it is <u>not possible</u> to construct a triangle with given angles.

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3 years ago

Which triangle most likely has the angles 56°, 48°, and 76°?

Anna007 [38]

Answer:

c

Step-by-step explanation:

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3 years ago

Gayle installed a rectangular section of hardwood flooring measuring 12 ft by 12 ft in her family room. She plans on increasing

icang [17]

The ansa is 256=(12+x)(12+x)

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2 years ago