All categories

3 years ago

The nth term of a sequence is 3n+2, work out the first three terms of the sequence

Mathematics

2 answers:

sammy [17]3 years ago

4 0

Step-by-step explanation:

hgfhwjnsksjehefebhxjddkdjdjydudsisi

vova2212 [387]3 years ago

4 0

Answer:

5, 8, 11

Step-by-step explanation:

To find the first 3 terms substitute n = 1, 2, 3 into n th term rule, that is

a₁ = 3(1) + 2 = 3 + 2 = 5

a₂ = 3(2) + 2 = 6 + 2 = 8

a₃ = 3(3) + 2 = 9 + 2 = 11

The first 3 terms are 5, 8, 11

You might be interested in

HELP The solutions to the equation 2cosθ−sinθ=0 for 0∘≤θ≤360∘ are

konstantin123 [22]

Answer:

θ ∈ { 90 ∘ , 210 ∘ , 270 ∘ , 330 ∘ }

step by step explanation:

Factoring the left side of

2 sin ( θ ) cos ( θ ) + cos ( θ ) = 0

gives

cos ( θ ) ⋅ [ 2 sin ( θ ) + 1 ] = 0

Which implies (for θ ∈ [ 0 , 360 ∘])

either cos ( θ ) = 0

→ θ = 90 ∘ or 270 ∘

2 sin ( θ ) + 1 = 0

→ sin ( θ )=− 1 2 → θ = 210 ∘ or 330 ∘

→ θ = 210∘ or 330∘

8 0

2 years ago

Last year, the average monthly revenue at the Richmond Times newspaper was $82,980. So far this year, the average has been 25% m

Lena [83]

Answer:

103,725

Step-by-step explanation:

82,980x.25+82,980

8 0

3 years ago

The product of two numbers is 48, and one of the numbers is 12. Find the other number.

Anuta_ua [19.1K]

Two numbers, one being 12, are multiplied to equal 48.

Therefore, the answer is B) 12x = 48

7 0

3 years ago

Read 2 more answers

Company B: starting salary-28,000 Yearly salary increase-2,400

Naya [18.7K]

Answer:

Sharla, 4400

Step-by-step explanation:

Paul's Salary:

Paul started at company B. Starting salary of company B is $ 28,000 with a yearly increase of $ 2,400. Paul's Salary in first year will be 28,000. In second year his salary will be 28000 + 2400, in 3rd year his salary will be: 28000 + 2(2400) and so on.

Since, the increase in Paul's salary every year is $ 2400, the increase in his salary after 10 years or in 10th year would be = 2400 x 9 = $ 21,600

So, his total salary in 10th year would be = 28000 + 21600 = $ 49,600

Sharla's Salary:

Sharla started at company C. Starting salary of company C is $ 36,000 with a yearly increase of $ 2,000.

Since, the increase in Sharla's salary every year is $ 2000, the increase in her salary after 10 years or in 10th year would be = 2000 x 9 = $ 18,000

So, her total salary in 10th year would be = 36000 + 18000 = $ 54,000

Conclusion:

Sharla earned more in 10th year an amount equal to $ 4400. So the answer is:

In the last year, Sharla earned $4,400 more.

5 0

3 years ago

Whats 5+5+5+5+5+5+5+5+5+5+5+5+10+10+10+10 ????? Help!!!

Svetradugi [14.3K]

Answer:

100!!

Step-by-step explanation:

Hope this helps

3 0

3 years ago

Read 2 more answers