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Naya [18.7K]
3 years ago
6

Help me in confused and this thing has 40 QUESTIONS >:( WHYYYYYYYYYYYYYYYYYYYY

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

15

Step-by-step explanation:

Base=bottom

height=vertical

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Putting the equations in slope-intercept form changes the system from
myrzilka [38]

15x+9y=36 \rightarrow y=-\frac{5}{3}x+4 \\ \\ 10x + 6y = 36 \rightarrow y=-\frac{5}{3}x+6

The lines are parallel.

The slopes are equal.

<h2>Explanation:</h2>

The standard form of the equation of a line is given by the form:

Ax+By=C \\ \\ \\ Where: \\ \\ A \ is \ a \ positive \ integer \\ \\ B,C \ are \ integers

On the other hand, the slope-intercept form of the equation of a line is given by the form:

y=mx+b \\ \\ \\ m:Slope \\ \\ b:y-intercept

So let's convert each equation from the standard form to the slope-intercept form:

So, for the first equation:

15x+9y=36 \\ \\ Solving \ for \ y: \\ \\ 9y=-15x+36 \\ \\ y=\frac{-15x+36}{9} \\ \\ y=-\frac{5}{3}x+4

So, for the second equation:

10x + 6y = 36  \\ \\ Solving \ for \ y: \\ \\ 6y=-10x+36 \\ \\ y=\frac{-10x+36}{6} \\ \\ y=-\frac{5}{3}x+6

As you can see both equations have the same slope but different y-intercepts meaning that they are parallel. So these are the correct options:

The lines are parallel.

The slopes are equal.

<h2>Learn more:</h2>

Graph linear equations: brainly.com/question/13799715

#LearnWithBrainly

6 0
3 years ago
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Identify the vertex<br><br> y= —(x — 6)^2 + 2
alisha [4.7K]
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Mark brainliest please

Hope this helps you
8 0
3 years ago
If the following data were linearized using logarithms, what would be the
oksano4ka [1.4K]

Answer:

55

Step-by-step explanation:

3 0
3 years ago
Are 19/8 and 2.375 equivalent and why
Nuetrik [128]

Answer:

Yes.

Step-by-step explanation:

They are equivalent because if you divide 19 by 8, the result is 2.375.

4 0
3 years ago
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Solve and check <br> 2/3y =6 <br> A.1/9 <br> B.1/4<br> C.9<br> D.4
kotegsom [21]
\frac{2}{3}y=6\ \ \ \ |divide\ both\ sides\ by\ \frac{2}{3}\ /multiply\ by\ \frac{3}{2}/\\\\y=6\cdot\frac{3}{2}\\\\y=\frac{6}{1}\cdot\frac{3}{2}\\\\y=\frac{\not6^3\cdot3}{1\cdot\not2_1}\\\\y=\frac{3\cdot3}{1\cdot1}\\\\y=\frac{9}{1}\\\\\boxed{y=9}\leftarrow answer\ \boxed{C}

check:\\\\/put\ the\ value\ of\ y=9\ to\ the\ equation\ \frac{2}{3}y=6/\\\\\frac{2}{3}\cdot9=6\\\\\frac{2}{3}\cdot\frac{9}{1}=6\\\\\frac{2}{\not3_1}\cdot\frac{\not9^3}{1}=6\\\\\frac{2}{1}\cdot\frac{3}{1}=6\\\\2\cdot3=6\\\\\boxed{6=6}\leftarrow TRUE


8 0
4 years ago
Read 2 more answers
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