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3 years ago

Solve and check 2/3y =6 A.1/9 B.1/4 C.9 D.4

2 answers:

8 0

$\frac{2}{3}y=6\ \ \ \ |divide\ both\ sides\ by\ \frac{2}{3}\ /multiply\ by\ \frac{3}{2}/\\\\y=6\cdot\frac{3}{2}\\\\y=\frac{6}{1}\cdot\frac{3}{2}\\\\y=\frac{\not6^3\cdot3}{1\cdot\not2_1}\\\\y=\frac{3\cdot3}{1\cdot1}\\\\y=\frac{9}{1}\\\\\boxed{y=9}\leftarrow answer\ \boxed{C}$

$check:\\\\/put\ the\ value\ of\ y=9\ to\ the\ equation\ \frac{2}{3}y=6/\\\\\frac{2}{3}\cdot9=6\\\\\frac{2}{3}\cdot\frac{9}{1}=6\\\\\frac{2}{\not3_1}\cdot\frac{\not9^3}{1}=6\\\\\frac{2}{1}\cdot\frac{3}{1}=6\\\\2\cdot3=6\\\\\boxed{6=6}\leftarrow TRUE$

Archy [21]3 years ago

5 0

$\frac{2}{3} *y=6 \\ \\ y=6: \frac{2}{3} =6* \frac{3}{2} = \frac{18}{2} =9

$

So the answer is C. 9

2/3* 9=(2*9)/3=18/3= 6 (true)

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Evaluate 10x+18 when x=5

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Step-by-step explanation:

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Find the original price of a pair of shoes if the sale price is $40 after a %20% discount.

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3 years ago

Algebra II Help??? Subtracting Fractions (2x)/(y^2-x^2) - (x)/(y-x)

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Make bottom number same

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2 years ago

A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win

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Answer:

The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25% of their capacity, how much energy, in kilowatt-hours, can the region's wind farms generate in one year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year

Part B

Given that the average household in the region uses about 10,000 kilowatt-hours of energy each year, how many households can be powered by these wind farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

Amount of households = 4,818'000,000/10,000 = 481,800

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3 years ago