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Mnenie [13.5K]
3 years ago
6

Evaluate tan(sin^-1 (-4/5))

Mathematics
1 answer:
defon3 years ago
5 0
\theta=\sin ^{-1}\left(-\dfrac{4}{5} \right ) is in the fourth quadrant. Hence,

\tan \theta


From a right triangle (check out the attachment) we get

\bullet\;\;\cos \theta=\dfrac{3}{5}\\\\\\ \bullet\;\;\tan \theta=-\dfrac{4}{3}\\\\\\\\ \therefore~~\boxed{\begin{array}{c} \tan\left(\sin^{-1} \left(-\dfrac{4}{5} \right )\right)=-\dfrac{4}{3} \end{array}}

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