Answer:
The solutions are:
or
.
Step-by-step explanation:
The given equation is ![x^2=5x+14](https://tex.z-dn.net/?f=x%5E2%3D5x%2B14)
We rewrite in the standard quadratic form to obtain;
![x^2-5x-14=0](https://tex.z-dn.net/?f=x%5E2-5x-14%3D0)
We split the middle term with -7,2 because their product is -14 and their sum is -5.
![x^2-7x+2x-14=0](https://tex.z-dn.net/?f=x%5E2-7x%2B2x-14%3D0)
Factor by grouping;
![x(x-7)+2(x-7)=0](https://tex.z-dn.net/?f=x%28x-7%29%2B2%28x-7%29%3D0)
![(x-7)(x+2)=0](https://tex.z-dn.net/?f=%28x-7%29%28x%2B2%29%3D0)
Either
or
.
Either
or
.
Area = Length * Width = l * w
l = x + 2
w = 2x - 5
Area = (x + 2)(2x - 5) = 56
Area = 2x^2 -x - 10 = 56
Area = 2x^2 - x - 66 = 0 Now you have to factor this thing.
Area = (2x + 11)( x - 6) = 0 This is more or less done by guessing.
2x + 11 = 0 can't work. x would be negative.
x - 6 = 0
x = 6.
Check
=====
l = x + 2
l = 6 + 2
l = 8
w = 2*x - 5
w = 2*6 - 5
w = 12 - 5
w = 7
l*w = 8*7 = 56. It checks.
If this is the best answer you get, could you consider a Brainly? I need 2 of them to move up.
1. x=5
2. x= 4
3. x=7
4. x=6
last two i don’t have a graph sorry
Associative property of multiplication
Answer:
4
Step-by-step explanation: