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mel-nik [20]
3 years ago
14

Find the area of a regular pentagon with a side of 10cm and an apothem of 6.9cm

Mathematics
1 answer:
svetlana [45]3 years ago
7 0
Area = 172.05 i think
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Isabella backed cookies for 3 hours. She spent the same amount of time baking each batch. It took her one eighth an hour to bake
katovenus [111]

I believe it is 24 batches:

because there are 8/8 in one hour, so you multiply that by three. which would give you 24!

5 0
3 years ago
The velocity v and maximum height h of the water being pumped into the air are related by the equation v=\sqrt(2gh) where g is t
Whitepunk [10]

The velocity v and maximum height h of the water being pumped into the air are related by the equation

v= \sqrt{2gh}

where g = 32

(a) To find the equation that will give the maximum height of the water , solve the equation for h

v= \sqrt{2gh}

Take square root on both sides

v^2 = 2gh

Divide by 2g on both sides

\frac{v^2}{2g} = h

So maximum height of the water h = \frac{v^2}{2g}

(b) Maximum height h= 80

velocity v= 75 ft/sec

Given g = 32

h = \frac{v^2}{2g}

h = \frac{75^2}{2*32}

h= 87.89 ft

The pump withe the velocity of 75 ft/sec reaches the maximum height of 87.89 feet. 87.86 is greater than the maximum height 80 feet.

So the pump will meet the fire department needs.

8 0
3 years ago
What is the greatest common factor that could be used to reduce 36/90
TEA [102]
I got 18 for this one............
3 0
3 years ago
Read 2 more answers
What is 6.5% of 4300 round to the nearest hundredth
muminat

Answer:

279.50

Step-by-step explanation:

4,300 x 0.065 = 279.50. Hope this helps!

5 0
3 years ago
AACB ~AEFD<br> x = [?]<br> Enter your answer in decimal form.
tia_tia [17]

Answer:

<h2>11.4</h2>

Solution,

∆ ACB = ∆ EFD

finding the value of X,

\frac{x}{3.8}  =  \frac{15}{5}

Apply cross product property

x \times 5 = 15 \times 3.8

Calculate the product

5x = 57

Divide both sides by 5

\frac{5x}{5}  =  \frac{57}{5}

Calculate

x = 11.4

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
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