Remember
![x^ \frac{m}{n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
and
and
(x^m)^n=x^(mn)
so
![((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}](https://tex.z-dn.net/?f=%20%28%287x%5E3%29%28y%5E2%29%29%5E%20%5Cfrac%7B2%7D%7B7%7D%20%3D%20%5Csqrt%5B7%5D%7B%28%287x%5E3%29%28y%5E2%29%29%5E2%7D%20)
=
![\sqrt[7]{((7x^3)^2(y^2)^2)}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%287x%5E3%29%5E2%28y%5E2%29%5E2%29%7D%20)
=
![\sqrt[7]{((7^2x^6)(y^4))}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%287%5E2x%5E6%29%28y%5E4%29%29%7D%20)
=
![\sqrt[7]{((49x^6)(y^4))}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B%28%2849x%5E6%29%28y%5E4%29%29%7D%20)
=
![\sqrt[7]{49x^6y^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B7%5D%7B49x%5E6y%5E4%7D%20)
and
and
(x^m)^n=x^(mn)
so
Find the area of a regular pentagon with a side of 10cm and an apothem of 6.9cm
1 answer:
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Answer:
Domain: {-6, -1, 7}
Range: {-9, 0, 9}
The relation is not a function.
Step-by-step explanation:
Given the relation: t{(−1,0),(7,0),(−1,9),(−6,−9)}
In the ordered pairs:
- The domain is the set of all "x" values
- The range is set of all "y" values
- We do not need to list any repeated value in the range/domain more than once.
Domain: {-6, -1, 7}
Range: {-9, 0, 9}
Next, we determine whether the relation is a function.
For a relation to be a function, each x must correspond with only one y value.
However, as is observed in the mapping attached below:
- f(-1)=0
- f(-1)=9
The x-value (-1) corresponds to two y-values (0 and 9)
Therefore, the relation is not a function.
Answer:
12
Step-by-step explanation:
The average is calculated as
average = =
=
= 12