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mel-nik [20]
3 years ago
14

Find the area of a regular pentagon with a side of 10cm and an apothem of 6.9cm

Mathematics
1 answer:
svetlana [45]3 years ago
7 0
Area = 172.05 i think
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Use the following diagram to find the angle measures of the triangle, rounded to the nearest degree.
nadezda [96]

Answer:

m∠A = 30°

m∠B = 80°

m∠C = 70°

Step-by-step explanation:

By applying cosine rule in the given triangle,

b² = a² + c² - 2ac[cos(∠B)]

From the given triangle,

a = 14 m

b = 28 m

c = 24 m

(28)² = (14)² + (24)² - 2(14)(24)cos(B)

784 = 196 + 576 - 672cos(∠B)

cos(∠B) = 0.1786

∠B = \text{cos}^{-1}(0.1786)

∠B = 79.71°

∠B = 80°

By applying sine rule in the given triangle,

\frac{\text{sinA}}{a}= \frac{\text{sinB}}{b}= \frac{\text{sinC}}{c}

\frac{\text{sinA}}{14}= \frac{\text{sin(79.71)}}{28}= \frac{\text{sinC}}{24}

\frac{\text{sinA}}{14}= \frac{\text{sin(79.71)}}{28}

\text{sinA}= \frac{\text{sin(79.71)}\times 14}{28}

sinA = 0.491958

A = 29.47°

A ≈ 30°

By applying triangle sum theorem,

m∠A + m∠B + m∠C = 180°

30° + 80° + m∠C = 180°

m∠C = 70°

4 0
3 years ago
If the distance from 0 to x on a number line is equal to 5, then –5 + x = 0
harkovskaia [24]
In the problem -5+x=0,  x=5
6 0
3 years ago
Can anybody tell me how to turn the equations above into slope intercept form so I can graph it?
rjkz [21]

Answer:

First then second answer below

Step-by-step explanation:

-x+y 4

-1/-1=1      x=1    y=1  

y/1=1/1+4/1

y=1x+4

-x+7y 21

-1/-1=1

7y/7=1/7+21/7

y=1/7x+3

7 0
2 years ago
Solve formula as indicated - d = 1/2 at^2 for a
11Alexandr11 [23.1K]
Hope this might help u

7 0
3 years ago
Find the component form of the vector that translates P(4,5) to p'.
olga_2 [115]

Answer:

The component form of the vector P'P is \left \langle -7, 2 \right \rangle

Step-by-step explanation:

The component form of the vector that translates P(4, 5) to P'(-3, 7), is given as follows;

The x-component of the vector = The difference in the x-values of the point P' and the point P = -3 - 4 = -7

The y-component of the vector = The difference in the y-values of the point P' and the point P = 7 - 5 = 2

The component form of the vector P'P = \left \langle -7, 2 \right \rangle

6 0
3 years ago
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