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zzz [600]
2 years ago
6

At the beginning of an experiment, a scientist has 132 grams of radioactive goo. After 135 minutes, her sample has decayed to 8.

25 grams.
what is the half-life of the goo in minutes?

find a formula for G(t), the amount of goo remaining at time t. G(t)=

how many grams of goo will remain after 47 minutes
Mathematics
1 answer:
Nataliya [291]2 years ago
4 0

Answer:

  • 33.75 minutes
  • G(t) = 135(1/2)^(t/33.75)
  • 51.42 grams

Step-by-step explanation:

Based on the given numbers, we know the decay factor is ...

  8.25/132 = 1/16

in 135 minutes. We recognize 1/16 = (1/2)^4, so is 4 half-lives.

a) The half-life of goo is (135 min)/4 = 33.75 minutes

__

b) A formula for the amount remaining could be ...

  G(t) = 135(1/2)^(t/33.75)

__

c) After 47 minutes, the amount remaining is ...

  G(47) = 135(1/2)^(47/33.75) ≈ 51.42 . . . grams

_____

<em>Comment on the solution</em>

The general form of a decay equation can be ...

  g(t) = (initial value)(decay factor)^(t/(decay time for the given factor))

For our G(t), we used a decay factor of 1/2 and the half-life time of 33.75 minutes.

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y=5x^2+7 is Non-Linear Functions

Option B is correct option.

Step-by-step explanation:

We need to identify Non-Linear Functions from the equations given.

First we will define Non-Linear Functions

<u>Linear Functions</u>

A function having exponent of variable equal to 1 or of the form y=c, where c is constant is called linear function.

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Option B is correct option.

Keywords: Linear and Non-Linear Functions

Learn more about Linear and Non-linear functions at:

  • brainly.com/question/12363217
  • brainly.com/question/4326955

#learnwithBrainly

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