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3 years ago

HELP FAST TO WHOEVER CAN PLEASE !!

Mathematics

1 answer:

DiKsa [7]3 years ago

7 0

It was reflected across the x-axis

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Describe a sequence of three transformations of ABC that will produce the image A’ B’ C’.

Leokris [45]

Answer:

Reflect over x-axis, Translate 5 units right, Dilate by a factor of 2

Step-by-step explanation:

I think this is correct The dilation probably isn't but those are the three transformations. But i am pretty sure i am right.

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3 years ago

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Marianna [84]

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Which expression is equivalent to<br> ^3 sqrt 1/1000 c^9 d^12

tamaranim1 [39]

Answer:

$\sqrt[3]{ \frac{1}{1000} {c}^{9} {d}^{12} } \\ = \frac{1}{10} {c}^{3} {d}^{4}$

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3 years ago

Which product is positive?<br> ( 13 ( 31 )<br> ( 31 )<br> (3) ( 13 (1)

Anastaziya [24]

The first one because it’s (13(31)

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4 years ago

Find the smallest positive integer solution to the following system of congruences: x = 0 (mod 5) x = 8 (mod 11) The solution is

igomit [66]

Answer:

The smallest positive integer solution to the given system of congruences is 30.

Step-by-step explanation:

The given system of congruences is

$x=0(mod5)$

$x=8(mod11)$

where, m and n are positive integers.

It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as

$x=5m$

$x=11n+8$

$5m\cong 11n+8$

Now, we can say that m>n because m and n are positive integers.

For n=1,

$5m=11(1)+8=19$

$5m=19$

19 is not divisible by 5 so m is not an integer for n=1.

For n=2,

$5m=11(2)+8$

$5m=30$

$m=6$

The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

$x=5(6)=30$

Therefore the smallest positive integer solution to the given system of congruences is 30.

8 0

3 years ago