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elena-14-01-66 [18.8K]
3 years ago
8

Malika charges $7.20 per hour for babysitting.she babysits 4 hours each week.she spends $10 per week and puts the rest of her ea

rnings in a saving account.after 12 weeks,Malika's grandparents put a gift of money in her savings account that is equal to 0.25 times the amount she has saved from babysitting earning.How much money does Malika have in her savings account after the gift from her grandparents? Show your work
Mathematics
2 answers:
Vika [28.1K]3 years ago
6 0

Answer: Malika has $282.00



denis23 [38]3 years ago
3 0
7.2 times 4=28.8-10=18.8
she saves 18.8 dollars per week.
18.8 times 12=225.6
after 12 weeks she has saved 225.6 dollars
225.6 times 0.25=56.4
her grandparents giver her 56.4 dollars
56.4+225.6=282
she has 282 dollars
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Step-by-step explanation:

We want to find the remainder when 6x^(5) + 4x⁴ - 27x³ - 7x² + 27x + 3/2 is divided by (2x² - 3)²

Let's expand (2x² - 3)² to give ;

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______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

First of all, we'll divide the term with the highest power inside the long division symbol by the term with the highest power outside the division symbol. This will give;

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______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

We now subtract the new multiplied term beneath the original one from the original one to get;

3/2x³

______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

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______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

22x⁴+(27/2)x³+27x +3/2

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¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

We now subtract the new multiplied term beneath the immediate one from the immediate one to get;

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______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

6x^(5)-18x⁴-(27/2)x³

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

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We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

(3/2)x³ + (11/2)x² + (159/8)x

______________________

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6x^(5)-18x⁴-(27/2)x³

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22x⁴+(27/2)x³-7x²+27x +3/2

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We now subtract the new multiplied term beneath the immediate one from the immediate one to get;

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______________________

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22x⁴+(27/2)x³-7x²+27x +3/2

22x⁴-66x³ + (99/2)x²

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

(159/2)x³-(113/2)x²+27x+(3/2)

(159/2)x³-(477/2)x²+(1431/8)x

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182x²-(1215/8)x + (3/2)

We'll now divide the term in new polynomial gotten with the highest power by the term with the highest power outside the division symbol. This gives;

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______________________

4x²-12x+9 |6x^(5)+4x⁴-27x³-7x²+27x+3/2

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