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erma4kov [3.2K]
2 years ago
6

If you misspell a word in your Java program it may be true that I. the program will not compile II. the program may compile, but

not run III. the program may compile and run but still have a logic error
Computers and Technology
1 answer:
yaroslaw [1]2 years ago
5 0

Answer:

option I

Explanation:

If you misspell a word in your Java program it may be true that the program will not compile

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In _____ conversion of the implementation phase of the systems development life cycle (SDLC), the old and new systems run simult
coldgirl [10]

Answer:

b. parallel

Explanation:

According to my experience on information technology, I can say that based on the information provided within the question the term being mentioned is called Parallel Conversion. Like mentioned in the question this term refers to when two systems run at the same time while transferring operations in order to make sure that everything is running correctly and are outputting the same results.

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3 years ago
Which of te following ranges of cells is correctly named
Natasha_Volkova [10]
D it is because its .a5.g1
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Are self driving cars essential for the future of transportation
azamat
Yes, I think so at least because what about those who can't physically drive? They would want the experience of being in the driver's seat.
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3 years ago
The following checksum formula is widely used by banks and credit card companies to validate legal account numbers: d0 + f(d1) +
Aleksandr [31]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to import Scanner class

public class ISBN

{   public static void main(String[] args)  { // start of main() function body

   Scanner s = new Scanner(System.in); // creates Scanner object

//prompts the user to enter 10 digit integer

   System.out.println("Enter the digits of an ISBN as integer: ");    

   String number = s.next(); // reads the number from the user

   int sum = 0; // stores the sum of the digits

   for (int i = 2; i <= number.length(); i++) {

//loop starts and continues till the end of the number is reached by i

          sum += (i * number.charAt(i - 1) ); }

/*this statement multiplies each digit of the number with i and adds the value of sum to the product result and stores in the sum variable*/

          int remainder = (sum % 11);  // take mod of sum by 11 to get checksum  

   if (remainder == 10)

/*if remainder is equal to 10 adds X at the end of given isbn number as checksum value */

  { System.out.println("The ISBN number is " + number + "X"); }

  else

// displays input number with the checksum value computed

 {System.out.println("The ISBN number is " + number + remainder); }  }  }  

Explanation:

This program takes a 10-digit integer as a command line argument and uses Scanner class to accept input from the user.

The for loop has a variable i that starts from 2 and the loop terminates when the value of i exceeds 10 and this loop multiplies each digit of the input number with the i and this product is added and stored in variable sum. charAt() function is used to return a char value at i-1.

This is done in the following way: suppose d represents each digit:

sum=d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5 + d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9

Next the mod operator is used to get the remainder by dividing the value of sum with 11 in order to find the checksum and stores the result in remainder variable.

If the value of remainder is equal to 10 then use X for 10 and the output will be the 10 digits and the 11th digit checksum (last digit) is X.

If the value of remainder is not equal to 10, then it prints a valid 11-digit number with the given integer as its first 10 digits and the checksum computed by sum % 11 as the last digit.  

8 0
3 years ago
Easy way of communication with people is one disadvantage of a network. *<br><br> 1.True<br> 2.False
Maksim231197 [3]

Answer:

false

because we are able to connect with people easily..

without have to wait for long time in the case of letters..

4 0
2 years ago
Read 2 more answers
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