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ki77a [65]
3 years ago
8

Mô tả những lợi ích của việc sử dụng đa xử lý không đồng nhất trong một hệ thống di động

Computers and Technology
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

gzvzvzvzbxbxbxb

Explanation:

hshzhszgxgxggdxgvdvsvzvzv

You might be interested in
C++
nikitadnepr [17]

Answer:

Check the explanation

Explanation:

<u>The Code</u>

#include <fstream>

#include <iostream>

#include <cmath>

#include <cstring>

#include <cstdlib>

#include <ctime>

using namespace std;

//Function Declarations

void fillArrayWithRandNos(int nos[],int size);

void displayArray(int nos[],int size);

double mean(int nos[],int size);

double variance(int nos[],int size);

double median(int nos[],int size);

int mode(int nos[],int size);

void histogram(int nos[],int size);

int main() {

  //Declaring variables

const int size=100;

srand(time(NULL));

 

// Creating array dynamically

int* nos = new int[size];

 

//Calling the functions

fillArrayWithRandNos(nos,size);

displayArray(nos,size);

cout<<"Mean :"<<mean(nos,size)<<endl;

cout<<"variance :"<<variance(nos,size)<<endl;

cout<<"Median :"<<median(nos,size)<<endl;

cout<<"Mode :"<<mode(nos,size)<<endl;

histogram(nos,size);

 

  return 0;

}

void fillArrayWithRandNos(int nos[],int size)

{

  for(int i=0;i<size;i++)

  {

      nos[i]=rand()%(45) + 55;

  }

}

void displayArray(int nos[],int size)

{

  cout<<"Displaying the array elements :"<<endl;

  for(int i=0;i<size;i++)

  {

      cout<<nos[i]<<" ";

      if((i+1)%10==0)

      cout<<endl;

  }

}

double mean(int nos[],int size)

{

  double sum=0;

  for(int i=0;i<size;i++)

  {

      sum+=nos[i];

  }

  return sum/size;

}

double variance(int nos[],int size)

{

  double avg=mean(nos,size);

 

double variance,sum=0;

for(int i=0;i<size;i++)

{

sum+=pow(nos[i]-avg,2);

}

//calculating the standard deviation of nos[] array

variance=(double)sum/(size);

return variance;

}

double median(int nos[],int size)

{

      //This Logic will Sort the Array of elements in Ascending order

  int temp;

  for (int i = 0; i < size; i++)

{

for (int j = i + 1; j < size; j++)

{

if (nos[i] > nos[j])

{

temp = nos[i];

nos[i] = nos[j];

nos[j] = temp;

}

}

}

 

int middle;

float med;

middle = (size / 2.0);

if (size % 2 == 0)

med = ((nos[middle - 1]) + (nos[middle])) / 2.0;

else

med = (nos[middle]);

return med;

}

int mode(int nos[],int size)

{

  int counter1 = 0, counter2, modevalue;

for (int i = 0; i < size; i++) {

counter2 = 0;

for (int j = i; j < size; j++) {

if (nos[i] == nos[j]) {

counter2++;

}

if (counter2 > counter1) {

counter1 = counter2;

modevalue = nos[i];

}

}

}

if (counter1 > 1)

return modevalue;

else

return 0;

}

void histogram(int nos[],int size)

{

  int hist[9]={0};

  for(int i=0;i<size;i++)

  {

      if(nos[i]>=55 && nos[i]<=59)

      {

      hist[0]++;

      }

      else if(nos[i]>=60 && nos[i]<=64)

      {

      hist[1]++;

      }

      else if(nos[i]>=65 && nos[i]<=69)

      {

      hist[2]++;

      }

      else if(nos[i]>=70 && nos[i]<=74)

      {

      hist[3]++;

      }

      else if(nos[i]>=75 && nos[i]<=79)

      {

      hist[4]++;

      }

      else if(nos[i]>=80 && nos[i]<=84)

      {

      hist[5]++;

      }

      else if(nos[i]>=85 && nos[i]<=89)

      {

      hist[6]++;

      }

      else if(nos[i]>=90 && nos[i]<=94)

      {

      hist[7]++;

      }

      else if(nos[i]>=95 && nos[i]<=99)

      {

      hist[8]++;

      }

  }

     

  cout<<"Displaying the count of numbers in each interval:"<<endl;

 

      int cnt=0;

  for(int i=55;i<=99;i+=5)

  {

  cout<<i<<"-"<<i+4<<"|"<<hist[cnt]<<endl;

 

      cnt++;

  }

 

  cout<<"Displaying the histogram :"<<endl;

  cnt=0;

  for(int i=55;i<=99;i+=5)

  {

  cout<<i<<"-"<<i+4<<"|";

  for(int j=0;j<hist[cnt];j++)

  {

      cout<<"*";

  }  

      cout<<endl;

      cnt++;

  }          

     

 

 

}

#########

___________________________

The output can be seen in the attached image below.

8 0
3 years ago
You will start by doing a bit of research on viewfinders and LCD displays on digital cameras. After you feel that you have an un
Lemur [1.5K]

Answer:

SOMEBODY ANSWER IT

Explanation:

JESUS C

3 0
3 years ago
_____ is a predefined format used for text the can include multiple font formatting features
seraphim [82]
The correct answer is



style
8 0
3 years ago
python A pet shop wants to give a discount to its clients if they buy one or more pets. The discount is equal to 20 percent of t
Artyom0805 [142]

Answer:

The following are the program in the Python Programming Language.

#define function

def discount(prices, isPet, nItems):

 # declare and initialize variables to 0

 i = 0

 cost = 0

 pets = 0

 item = 0

 item_Cost = 0

 #set the while loop

 while(i < nItems):

   #check the items of the variable

   if isPet[i]:

     #add and initialize in the cost

     cost += prices[i]

     #increament in the variable by 1

     pets += 1

   #otherwise

   else:

     #add and initialize in the item_Cost

     item_Cost += prices[i]

     #increament in the variable by 1

     item += 1

   #then increment in the variable by 1

   i += 1

 #check the pet is greater than equal to 1  

 #and item is greater than equal to 5

 if(pets >= 1 and item >=5):

   #then, print the message

   print("You receive discount")

   #set discount of the items

   discount = 0.2 * item_Cost

   # calculate bill after deducting discount

   bill = cost + item_Cost - discount

   #print the bill

   print("Final Bill amount is", bill)

 #otherwise

 else:

   #print the message

   print("You do not receive any discount")

   #calculate bill without deducting discount

   bill = cost + item_Cost

   #print the final bill

   print("Final Bill amount is", bill)

#set empty list type variables

price = []

pet = []

#set the infinite loop

while True:

 #get input from the user

 sprice = int(input("Enter the price (-1 to quit): "))

 #check that price is not equal to the -1

 if(sprice != -1):

   #add price in the list

   price.append(sprice)

   #ask for choice from the user

   choice = input("Is it a pet (Y / N)? ")

   #check the choice of the user is y or Y

   if(choice == 'Y' or choice == 'y'):

     # then, add in the pet

     pet.append(True)

   #otherwise

   else:

     #not add in the pet

     pet.append(False)

   print("")

 #break the loop

 else:

   break

#declare variable that store the length

items = len(price)

#call and initialize the variable

discount(price, pet, items)

<u>Output</u>:

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? y

Enter the price (-1 to quit): 69

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 41

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 52

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 74

Is it a pet (Y / N)? n

Enter the price (-1 to quit): -1

You receive discount

Final Bill amount is 361.6

Explanation:

<u>The following are the description of the program</u>.

  • Firstly, define the function 'discount()' and pass the arguments 'prices', 'isPet' and 'nItems' in its parameter.
  • Then, declare and initialize the variables 'i' to 0, 'item_Cost' to 0
  • , item to 0, 'cost' to 0 and 'pets' to 0.
  • Then, set the while loop to add the price of the items and the cost of the pets.
  • Set the if-else conditional statement to check the pet is greater than equal to 1 and the items are greater than equal to 5 then, set the discount and print the bill after deduction.
  • Otherwise, print the bill without deduction.
  • Finally, set two list type variable then, set the infinite while loop that gets input from the user and check that the variable is not equal to -1 then append the data in the list then again check the user input then append in pet otherwise not append in pet and break the loop. Then, set the variable that stores the length of the price and call the following function by passing arguments in its parameter.
8 0
3 years ago
Plzzz help! It’s due soon and I can’t figure it out
nignag [31]

Answer:

The answer is A or the first option.

Explanation:

3 0
3 years ago
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