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2 years ago

5

Select twvo ratios that are equivalent to 2: 12

1 answer:

Xelga [282]2 years ago

3 0

Answer:

1:6 and 8:48

Step-by-step explanation:

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what is true about every rotation? the image and pre-image are congruent. the image is larger than the pre-image. the image over

Rudiy27

I think the correct answer from the choices listed above is the first option. The statement that is true for every rotation would be that the image and pre-image are congruent. A<span>ll the rest deals with changing the rotated shape not a constant. Hope this helps.</span>

4 0

3 years ago

Read 2 more answers

What is the range for 25,25,21,28,37,26

lina2011 [118]

Answer:

16 is the range

Step-by-step explanation:

First, arrange the numbers from least to greatest.

21, 25, 25, 26, 28, 37

Then, subtract 21 (smallest number) from the 37 (biggest number).

37 - 21 = 16

So, the range is 16

Have a wonderful day!

7 0

2 years ago

a cell phone plan offers 250 minutes each month for 15.00 dollars per month. what is the cost per minute when a person uses all

Nezavi [6.7K]

It costs 0.06 cents each minute.

Explanation : $15/250 minutes = $0.06

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3 years ago

Find the general indefinite integral. (use c for the constant of integration. )

Vlada [557]

The indefinite integral will be $\int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)$

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

To know more about indefinite integral follow

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7 0

2 years ago

What value of x makes this equation true?

m_a_m_a [10]

2(2)-3=5-2(2)
4-3=5-4
1=1

The correct answer is A

5 0

3 years ago

Read 2 more answers