Juan and Ari went to the farmers market to buy fruit. Juan’s bag of apples that he bought weighed 31/7 pounds. Ari’s bag of oranges that she bought weighed 19/3 pounds. Using compatible fractions, estimate how much heavier Ari's bag is compared to Juan's bag.
A) 1 and one-half pounds
B) 2 pounds
C) 6 pounds
D) 10 and one-half pounds
Answer:
B: approximately 2 pounds
Step-by-step explanation:
Juan’s bag weighed 31/7 pounds
Ari's bag weighed 19/3 pounds.
We are told to use compatible fractions to determine the difference. Thus we have to make sure the denominator is the same;
For Juan, let's multiply both numerator and denominator by 3 to get; 93/21 pounds
For Ari, let's multiply both numerator and denominator by 7 to get; 133/21
Thus, difference is;
(133/21) - (93/21) = 40/21
This gives;
1.9 pounds heavier
This is approximately 2 pounds
Answer:
12.72
2.65/5 = 0.53
0.53x24= 12.72
Step-by-step explanation:
Answer:
y=.5x+8
Step-by-step explanation:
Answer: 42 feet
Step-by-step explanation:
Let the length be x
Therefore, width = 2/3x
Area = Length × Width
Therefore, x × 2/3x = 1176
2/3x² = 1176
Divide both side by 2/3
x² = 1176 ÷ 2/3
x² = 1176 × 3/2
x² = 1764
x = ✓1764
x = 42
The length is 42 feet
Answer:
Step-by-step explanation:
Let the total budget be x.
<u>Given condition:</u>
73% of total budget = 949
73% of x = 949
<u>Key:</u>
of => to multiply
% => out of 100
<u>Solution;</u>
![\displaystyle \frac{73}{100} \times x = 949\\\\Multiply \ \frac{100}{73} \ to \ both\ sides\\\\x=949 \times \frac{100}{73} \\\\x = \frac{94900}{73} \\\\x = \$ 1300\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B73%7D%7B100%7D%20%5Ctimes%20x%20%3D%20949%5C%5C%5C%5CMultiply%20%5C%20%5Cfrac%7B100%7D%7B73%7D%20%5C%20to%20%5C%20both%5C%20sides%5C%5C%5C%5Cx%3D949%20%5Ctimes%20%5Cfrac%7B100%7D%7B73%7D%20%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B94900%7D%7B73%7D%20%5C%5C%5C%5Cx%20%3D%20%5C%24%201300%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
