2 years ago

Find the angle between the following pairs of lines x^2+6xy +9y^2-4x +12y-5 =0

Mathematics

1 answer:

wlad13 [49]2 years ago

3 0

Answer:

+6xy+9y

+4x+12y−5=0

Step-by-step explanation:

+6xy+9y

+4x+12y−5=0

Comparing the equation with the general equation of second degree gives

a=1,b=9,h=3,g=2,f=6,c=−5

Angle between a pair of straight lines that is tanθ=

∣

a+b

−ab

∣

tanθ=

∣

1+9

9−1×9

∣

tanθ=0

⇒θ=tan

−

(0)=0

∘

Angle between the pair of straight lines is zero therefore the lines are parallel.

Hence proved

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Find the angle between the following pairs of lines x^2+6xy +9y^2-4x +12y-5 =0​

Find the angle between the following pairs of lines x^2+6xy +9y^2-4x +12y-5 =0