Answer:
BE is congruent to ED
Step-by-step explanation:
Answer:
A) see attached for a graph. Range: (-∞, 7]
B) asymptotes: x = 1, y = -2, y = -1
C) (x → -∞, y → -2), (x → ∞, y → -1)
Step-by-step explanation:
<h3>Part A</h3>
A graphing calculator is useful for graphing the function. We note that the part for x > 1 can be simplified:

This has a vertical asymptote at x=1, and a hole at x=2.
The function for x ≤ 1 is an ordinary exponential function, shifted left 1 unit and down 2 units. Its maximum value of 3^-2 = 7 is found at x=1.
The graph is attached.
The range of the function is (-∞, 7].
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<h3>Part B</h3>
As we mentioned in Part A, there is a vertical asymptote at x = 1. This is where the denominator (x-1) is zero.
The exponential function has a horizontal asymptote of y = -2; the rational function has a horizontal asymptote of y = (-x/x) = -1. The horizontal asymptote of the exponential would ordinarily be y=0, but this function has been translated down 2 units.
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<h3>Part C</h3>
The end behavior is defined by the horizontal asymptotes:
for x → -∞, y → -2
for x → ∞, y → -1
The subway car passes through 48 stations in 2hours
It is given that a subway car passes 4 stations every 10 mins.
Subway car is being referred to the metro system of New York city
It is known to us that an hour has 60 mins
We are given that subway car passes 4 stations every 10 mins
Therefore number of stations passed by subway car in 1 hour
= 60/10 x 4 = 24 stations
We are required to find the number of stations crossed by subway car in 2 hours
Therefore, number of stations crossed by subway car in 2 hours= 24 x 2
= 48 stations
Therefore, the subway car passes 48 stations in 2 hours
For further reference:
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