Question

50 points.

Answer 1

Answer:

1

Step-by-step explanation:

Using the rules of exponents

$(a^m)^{n}$ = $a^{mn}$

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$

Given

$(\frac{1}{x^{(a-b)}) } ^{a+b}$ × $(\frac{1}{x^{b+a}) } ^{b-a}$

= $\frac{1}{x^{(a-b)(a+b)} }$ × $\frac{1}{x^{(b+a)(b-a)} }$

= $\frac{1}{x^{(a^2-b^2)} }$ × $\frac{1}{x^{(b^2-a^2)} }$

= $\frac{1}{x^{(a^2-b^2+b^2-a^2)} }$

= $\frac{1}{x^{0} }$

= $\frac{1}{1}$

= 1

Answer 2

well you already got an answer so can i have free 25