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Helen [10]
3 years ago
8

Please help me asap thank u

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
The answer is 6 since the legs should be the same in a 45 45 90 triangle
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Find g(x), where g(x) is the translation 8 units left of f(x)=x
Olegator [25]

Using translation concepts, it is found that function g(x) is given by:

g(x) = x + 8.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, function g(x) is a translation 8 units left of f(x) = x, hence x -> x + 8 and:

g(x) = f(x +8) = x + 8.

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

8 0
3 years ago
Evaluate this expression when a=9
OlgaM077 [116]

Answer:

63

Step-by-step explanation:

a=9

7a

7(9)

63

6 0
3 years ago
1. Chelsea has 11 times as many art brushes as
Alexandra [31]
C = 11m c + m = 60

Substitute

11m + m = 60

12m = 60

m = 5

4 0
3 years ago
(b) Develop a probability distribution for x y. x y f(x y) 130 Incorrect: Your answer is incorrect. 80 Incorrect: Your answer is
GenaCL600 [577]

Answer:

P(X = x, Y = y) = f(x, y)

Step-by-step explanation:

Let X be a discrete random variable, and suppose that the possible values that it can assume are given by x1, x2,  x3, . . . , arranged in some order. Suppose also that these values are assumed with probabilities given by

P(X = xk) = f(xk)                k = 1, 2, . . . (1)

It is convenient to introduce the probability function, also referred to as probability distribution, given by

P(X = x) = f(x)

If X and Y are two discrete random variables, we define the joint probability function

of X and Y by

P(X = x, Y = y) = f(x, y)

where f(x, y) ≥ 0

5 0
3 years ago
Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?
oee [108]
The answer is \frac{x^{4/3}y^{3}}{3}.

The fraction is: \frac{4xy^{-2} }{12 x^{-1/3} y^{-5}  }
Let's rewrite it: \frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }

Since \frac{x^{a} }{x^{b}} =x^{a-b},
then:
*** \frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}
*** \frac{y^{-2} }{ y^{-5} }=  y^{-2-(-5)} = y^{-2+5} = y^{3}
______
\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}
8 0
3 years ago
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