Question

Factorize 2x⁴+x³-14x²-19x-6 no spam and kindly explain your answer!​

Answer 1

Step-by-step explanation:

Consider given the expression,

⇒2x4+x3−14x2−19x−6

⇒x3(2x+1)−(14x2+19x+6)

⇒x3(2x+1)−(14x2+7x+12x+6)

⇒x3(2x+1)−[7x(2x+1)+6(2x+1)]

⇒x3(2x+1)−(2x+1)(7x+6)

⇒(2x+1)(x3−7x−6)

Hence, this is the answer.

Answer 2

Answer:

As (x+2) and (x-3) are factors of p(x), therefore g(x) = (x+2)(x-3) = x² - x - 6 is a factor of p(x). Let divide p(x) by g (x)to obtain the quotient as a quadratic in x and then factorise the quotient. So , when you divide p(x) by g(x) you will get 2x² + 3x + 1.29-Jun-2019

Step-by-step explanation:

As (x+2) and (x-3) are factors of p(x), therefore g(x) = (x+2)(x-3) = x² - x - 6 is a factor of p(x). Let divide p(x) by g (x)to obtain the quotient as a quadratic in x and then factorise the quotient. So , when you divide p(x) by g(x) you will get 2x² + 3x + 1.29-Jun-2019