i'm not sure how to solve the first one but the second is 150
Answer:
Step-by-step explanation:
y-5=3(x+2)
y-5=3x+6
y-5-6=3x+6-6
y-1=3x
X2+16 is the prime <span>polynomial.
x2+16 is the only </span><span>polynomial that couldn't be factored out anymore
x2-36 --> (x-6)(x+6)
x2-7x+12 --> (x-3)(x-4)
x2-x-20 --> (x+5)(x-4)</span>
The answer is .015
Hope this helps
The radii of the frustrum bases is 12
Step-by-step explanation:
In the figure attached below, ABC represents the cone cross-section while the BCDE represents frustum cross-section
As given in the figure radius and height of the cone are 9 and 12 respectively
Similarly, the height of the frustum is 4
Hence the height of the complete cone= 4+12= 16 (height of frustum+ height of cone)
We can see that ΔABC is similar to ΔADE
Using the similarity theorem
AC/AE=BC/DE
Substituting the values
12/16=9/DE
∴ DE= 16*9/12= 12
Hence the radii of the frustum is 12
