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2 years ago

HELP!!!!!!!!!!!!!! What is a compound event? An independent event?

2 answers:

5 0

Suppose you flip a coin and roll a die at the same time. These are compound events. These events are independent. Independent events occur when the outcome of one event does not affect the outcome of the second event. Rolling a four has no effect on tossing a head.

marta [7]2 years ago

5 0

Answer:

here

Step-by-step explanation:

Suppose you flip a coin and roll a die at the same time. These are compound events. ... These events are independent. Independent events occur when the outcome of one event does not affect the outcome of the second event. Rolling a four has no effect on tossing a head

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A local fast-food restaurant can serve

Marizza181 [45]

Answer:

4 hours, 150 x 4 = 600 pls give brainliest

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3 years ago

A certain circle can be represented by the following equation. X^2+y^2-6x-6y+2=0.

pav-90 [236]

Answer

Step-by-step explanation:

7 0

2 years ago

Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un

stira [4]

Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = $2w+15$

width = $2w+9$

Area of road with pool = $(2w+15) (2w+9)$

$= 4w^2+30w+18w+135\\\\=4w^2+48w+135$

Area of road = (Area of road with pool ) -(area of pool)

$\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\ w=-14\ or \ w=2$

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0

3 years ago

Multiply x^2+5•x^3+7 <br> I’m getting x^5+5x^3+7x^2+35 But I’m not sure if I’m right

user100 [1]

Answer:

x⁵ + 5x³ + 7x² + 35

Step-by-step explanation:

(x² + 5) (x³ + 7)

To distribute binomials (expressions with two terms), you can use the FOIL method (First, Outer, Inner, Last):

x⁵ + 7x² + 5x³ + 35

To put into standard form, rearrange from highest power to lowest power:

x⁵ + 5x³ + 7x² + 35

6 0

3 years ago

SOS MAYDAY!!! URGENT HELP REQUIRED THIS IS NOT A DRILL WEEEEEEEEEEEEEEEEEWOOOOOOOOOOOOO

timurjin [86]

The answer choice is B I just took

8 0

3 years ago