Answer:
I need a question, then I will help
Step-by-step explanation:
3(1,000,000)=3,000,000
3(100,000)=300,000
2(100)=200
3,300,200
1st Side: 8
2nd Side: 2x - 1
3rd Side: x
(8) + (2x - 1) > x (2x - 1) + x > 8 (x) + (8) > 2x - 1
2x + 7 > x 3x - 1 > 8 8 > x - 1
2x > -7 3x > 9 9 > x
x > -3.5 (disregard) x > 3 x < 9
3rd Side: x ⇒ (3 < x < 9)
2nd Side: 2x - 1 ⇒ 2(3) - 1 < x < 2(9) - 1 ⇒ 5 < x < 17
Answer: the 3rd side must be between 3 and 9, the 2nd side must be between 5 and 17
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032