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2 years ago

6

Julian is a teaching assistant at a local community college. A tutor at the same college works the same hours as Justin but earn

s 15,000 less annually. The sum of of Justin’s annual salary and the titor’s salary is 102,000. How much does each earn

1 answer:

mafiozo [28]2 years ago

3 0

The equation for this would be 2x+15000=102,000
2x=87000
x=43500
julian makes 58500
and tutor makes 43500

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The two figures shown are congruent. Which statement is true?

zimovet [89]

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Answer:

(b) One figure is a rotation image of the other

Step-by-step explanation:

The axis of symmetry is horizontal for the left figure, and vertical for the right figure. The right figure has been rotated 90° CW from the left figure.

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3 years ago

1. What is the solution to the system of equations graphed below? (1 point)

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2 years ago

xYou volunteer to help drive children at a charity event to the zoo, but you can fit only 6 of the 16 children present in your

brilliants [131]

There are 8008 groups in total, in other to drive the children

<h3>How to determine the number of groups?</h3>

From the question, we have

Total number of children, n = 16
Numbers to children at once, r = 6

The number of group of children that could be carried at once is calculated using the following combination formula

Total = ⁿCᵣ

Where

n = 16 and r = 6

Substitute the known values in the above equation

Total = ¹⁶C₆

Apply the combination formula

ⁿCᵣ = n!/(n - r)!r!

So, we have

Total = 16!/10!6!

Evaluate

Total = 8008

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1 year ago

What is 3 x 4/5 equal too?

sineoko [7]

12/5 is the answer!

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3 years ago

Read 2 more answers

The endpoints of a diameter of a circle are (6,2) and (−2,5) . What is the standard form of the equation of this circle?

Paul [167]

Answer:

The standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

Step-by-step explanation:

Given that the end points of a diameter of a circle are (6,2) and (-2,5);

Now to find the standard form of the equation of this circle:

The center is (h,k) of the circle is the midpoint of the given diameter

midpoint formula is $M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Let $(x_{1},y_{1})$ and $(x_{2},y_{2})$ be the given points (6,2) and (-2,5) respectively.

$M=(\frac{6-2}{2},\frac{2+5}{2})$

$M=(\frac{4}{2},\frac{7}{2})$

$M=(2,\frac{7}{2})$

Therefore the center (h,k) is $(2,\frac{7}{2})$

now to find the radius:

The diameter is the distance between the given points (6,2) and (-2,5)

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

$=\sqrt{(-2-6)^2+(5-2)^2}$

$=\sqrt{(-8)^2+(3)^2}$

$=\sqrt{64+9}$

$=\sqrt{73}$

Therefore the radius is $\sqrt{73}$

i.e., $r=\sqrt{73}$

Therefore the standard form of the circle is

$(x-h)^2+(y-k)^2=r^2$

Now substituting the center and radiuswe get

$(x-2)^2+(y-\frac{7}{2})^2=(\sqrt{73})^2$

$(x-2)^2+(y-\frac{7}{2})^2=73$

Therefore the standard form of the given circle is

$(x-2)^2+(y-\frac{7}{2})^2=73$

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3 years ago