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Drupady [299]
2 years ago
8

Why can you not delete questions on here?????

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
4 0

We can't delete our questions on brainly because it has already been posted.

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PLEASE HELP ASAP!!!
Sonbull [250]
2x^2 - 7x - 6 = 0

x1 = \frac{- b  +  \sqrt{ {b}^{2} - 4ac }}{2a}
x2 = \frac{- b   -   \sqrt{ {b}^{2} - 4ac }}{2a}
where a=2
where b=-7
where c=-6

solve for x1 and x2

x1=4.21
x2=-0.71
6 0
2 years ago
5 x {3 x [9 - (4 + 1)]} + 20 ÷ 4 x 2 =
adell [148]
To solve a problem like this, we need to start with the innermost parenthesis. Doing that, we get to 4+1, evaluating it giving us 5. This turns our expression into 5 x {3 x [9 - 5]} + 20 ÷ 4 x 2.



Now, the innermost parenthesis is 9-5. Evaluating that gives us 4. Our expression is now 5 x {3 x 4} + 20 ÷ 4 x 2.



Once again, we go to the innermost parenthesis and evaluate whatever is there. This turns our expression into <span>5 x 12 + 20 ÷ 4 x 2.



Now, we can simply use order of operations to compute that the value of the expression is equal to 70. </span>
7 0
2 years ago
Read 2 more answers
For lunch, Kile can eat a sandwich with either ham or a bologna and with or without cheese. Kile also has the choice of drinking
Scorpion4ik [409]

Answer:

8

Step-by-step explanation:

Ham with or without cheese-2 choices

Bologna with or without cheese-2 choices

Bologna with cheese with water or juice-2 choices

Bologna without cheese with juice or water-2 choices

Ham with cheese with juice or water -2 choices

Ham without cheese with juice or water -2 choices

2+2+2+2=8

Kile has 8 choices for lunch

4 0
3 years ago
pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base
kaheart [24]

Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

__

We expect your answer is supposed to be Step 4.

7 0
3 years ago
Jonathan measured 2 cups of flour into a bowl on the counter. Then he spilled part of it, and now there is only 3/8 cup left. Ho
sveticcg [70]
He spilled 1 and 5/8 cups because 2-3/8= 1 5/8. To check that, use 1 5/8+ 3/8= 2 cups.
7 0
3 years ago
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