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attashe74 [19]
3 years ago
12

which of the following equations would contain the point (4,12) A. y=3/4x+6 B. y=-1/2x-14 C. y=1/2x+10 D. y=-2x+4​

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
4 0
C because plugging in 4 for the x value will give us a value of 12 for y.
y=1/2(4)+10
y=2+10
y=12
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What is the solution to y=12
Nimfa-mama [501]

Answer:

y=12

Step-by-step explanation:

This equation cannot be simplified further.

Hope this helped! :)

8 0
3 years ago
A biker moves 2.5 times faster than a walker. They started moving simultaneously in the same direction from the same point. In t
saveliy_v [14]

Answer:

The speed of the biker is 15

Step-by-step explanation:

First, you call the speed of the walker x, and the speed of the biker 2.5x.

Then you know that speed times time equals distance, so you set up and equation. You do x times 2, which is 2x, and then 2.5x times 2, which is 5x. Then, since the distance between them is 18 miles, the equation would be 5x-2x=18. You would get 3x=18, and x is 6. So 6 is the speed of the walker, and 6 times 2.5 = 15, so the speed of the biker is 15.


5 0
3 years ago
Read 2 more answers
∠1 and ∠2 are complementary angles. m∠1 is 5y+32 and m∠2 is 7y-14. Find m∠2 & show your work.
Ainat [17]
  • m<1+m<2=90

\\ \sf\longmapsto 5y+32+7y-14=90

\\ \sf\longmapsto 12y+18=90

\\ \sf\longmapsto 12y=72

\\ \sf\longmapsto y=6

  • m<2=7(6)-14=42-14=28[/tex]
7 0
3 years ago
Read 2 more answers
Plzzzzzz ans this quickly plzz
elixir [45]

Step-by-step explanation:

8.

Prime factorization of 48 is :

48=2\times  2 \times  2 \times  2 \times  3\\\\=2^4\times  3^1

Option (3) is true.

9.

Prime factorization of 19 is:

19 = 19 × 1

Option (c) is correct.

(10).

Prime factorization of 924 is:

924 = 2 x 2 x 3 x 7 x 11

= 2² x 3¹ x 7¹ x 11¹

Hence, this is the required solution.

5 0
3 years ago
Regular hexagon ABCDEF has vertices at A(4, 4!3), B(8, 4!3), C(10, 2!3), D(8, 0), E(4, 0) and F(2, 2!3).
marissa [1.9K]

Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:

A=\frac{3\sqrt{3}}{2} a^2

Where A is the area of the regular hexagon

a is the side length of the regular hexagon

Also, it's Perimeter is given by:

P=6a

Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.

A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Where d is the distance.

(x_1,y_1) and (x_2,y_2) are the coordinates of points D and E respectively. (please note that interchanging the values of the coordinates will not alter the distance d)

Applying the above formula we get:

d=\sqrt{(8-4)^2+(0-0)^2} =\sqrt{4^2}=4

\therefore d=4

We know that this distance is the side length of the given regular hexagon.

\therefore d=a=4

Now, if the sides of the given regular polygon are reduced by 40%, then the new length of the sides will be:

a_{small}=4-\frac{40}{100}\times 4=2.4

Thus, the area of the smaller hexagon will be:

A_{small}=\frac{3\sqrt{3}}{2} a_{small}^2=\frac{3\sqrt{3}}{2} (2.4)^2\approx14.96 unit squared

and the new smaller perimeter will be:

P_{small}=6a_{small}=6\times 2.4=14.4 unit

Which are the required answers.

5 0
3 years ago
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