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3 years ago

hint Find the hypotenuse and then subtract that from the distance he actually traveled.

Mathematics

1 answer:

icang [17]3 years ago

5 0

Answer:

10 miles

Step-by-step explanation:

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Question 5 (1 point)

RoseWind [281]

Answer:c

Step-by-step explanation:

7 0

3 years ago

The points (0, 5) and (4, 13) lie on the graph of a linear function. What is the rate of change of the function?

Viefleur [7K]

The rate of change is the slope of this line
m = (y2 - y1)/(x2 - x1) = (13 - 5)/(4 - 0) = 8/4 = 2

6 0

3 years ago

Solve. 10x^2 = 6 + 9x10x 2 =6+9x10, x, start superscript, 2, end superscript, equals, 6, plus, 9, x Choose 1 answer: Choose 1 an

yulyashka [42]

Answer:

Option B.

Step-by-step explanation:

If a quadratic equation is defined as

$ax^2+bx+c=0$ .... (1)

then the quadratic formula is

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

The given equation is

$10x^2=6+9x$

It can rewritten as

$10x^2-9x-6=0$ .... (2)

On comparing (1) and (2) we get

$a=10,b=-9,c=-6$

Using quadratic formula we get

$x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(10)(-6)}}{2(10)}$

$x=\dfrac{9\pm \sqrt{81+240}}{20}$

$x=\dfrac{9\pm \sqrt{321}}{20}$

Therefore, the correct option is B.

6 0

3 years ago

Read 2 more answers

Please answer the question in the picture.

ASHA 777 [7]

Answer:

C.) The relationship is proportional

Step-by-step explanation:

If D is true, then it is not proportional, constants of proportionality must not include multuplting or subtracting from anything.

Also quick way to tell— the line doesn’t start from 0,0

4 0

3 years ago

In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :

Grace [21]

Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

$\angle DIH\cong \angle EGH$ as alternate interior angles;
$\angle DHI\cong \angle GHE$ as vertical angles;
$DH\cong HE$ because point H bisects segment DE (given).

Thus,

$\triangle DIH\cong \triangle EGH$ by AAS postulate

4 0

3 years ago

**hint** Find the hypotenuse and then subtract that from the distance he actually traveled.

hint Find the hypotenuse and then subtract that from the distance he actually traveled.