A: 208cm
B: 27cm
C: 30,000cm
Hope this helps!
]Eigenvectors are found by the equation

implying that

. We then can write:
And:
Gives us the characteristic polynomial:

So, solving for each eigenvector subspace:
![\left [ \begin{array}{cc} 4 & 2 \\ 5 & 1 \end{array} \right ] \left [ \begin{array}{c} x \\ y \end{array} \right ] = \left [ \begin{array}{c} -x \\ -y \end{array} \right ]](https://tex.z-dn.net/?f=%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bcc%7D%204%20%26%202%20%5C%5C%205%20%26%201%20%5Cend%7Barray%7D%20%5Cright%20%5D%20%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bc%7D%20x%20%5C%5C%20y%20%5Cend%7Barray%7D%20%5Cright%20%5D%20%3D%20%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bc%7D%20-x%20%5C%5C%20-y%20%5Cend%7Barray%7D%20%5Cright%20%5D%20)
Gives us the system of equations:
Producing the subspace along the line

We can see then that 3 is the answer.
a quadrilateral has 4 angles that add up to 360 degrees
x + 80+110+ 75 = 360
combine like terms
x + 265 = 360
subtract 265 from each side
x + 265 -265 =360 -265
x = 95
Choice C
<span>It must be the same as it was when constructing the arc above P.</span>
Answer:
C. Supplementary angles
Step-by-step explanation:
Given
<AFB = 72
Required
Relationship of <AFB and <AFD
<AFB and <AFD are on a straight line and angle on a straight line is 180
From the presentation of both angles,
<AFB + <AFD = 180
Substitute 72 for <AFB
72 + <AFD = 180
Make <AFB the subject of formula
<AFD = 180 - 72
<AFD = 108
Since both <AFB and <AFD sums to 180, then they are supplementary angles.
Hence, the relationship between both angles is supplementary angles