Answer:
The length of the line segment AC is equal to 14
Step-by-step explanation:
The triangle above is an isosceles triangle, In an Isosceles triangle the two angles; B and C are the same, hence the two sides; AB and AC are also the same.
AB=2x and AC= 3x - 7
AB = AC
which implies;
2x = 3x - 7
subtract 3x from both-side of the equation
2x - 3x = 3x -3x -7
-x = -7
Multiply through by -1
x = 7
But we were ask to find the the length of the line segment AC
AC = 3x - 7
substituting x = 7 into the above equation will yield;
AC = 3(7) - 7 = 21 - 7 =14
Therefore the length of the line segment AC is equal to 14
Step-by-step explanation:
<h2>We first find the area of a trapezium and rectangular face</h2><h2>Fourmula to find the are of a trapezium is:</h2><h3>Area=1/2*(B+b)*h</h3><h3> =1/2*3.7*1.9</h3><h3> =3.515m²</h3><h2 /><h2>Since every rectangular face is different we gotta find each of them</h2>
<h3>Area1=4.8*2.1</h3><h3> =10.08 m²</h3><h3>Area2=4.8*1.4=6.72m²</h3><h3>Area3=4.8*2.3=11.05m²</h3><h3>Area4=4.8*1.9=9.12m²</h3>
<h3 /><h3>Now we find the area of the whole prism</h3><h3>Area=3.515*2+10.08+6.72+11.05+9.12</h3><h3>Area=44m²</h3>
<h2>Sorry my wireless went down!!!</h2><h2>Hope this helps and you already know what I would like to get</h2>
The sinusoidal function graph has a period of 2·π and a minimum point
with coordinates (-0.5·n·π, -6) where n = -5, -1, 3, ...
Response:
- The minimum value of the function is -6
<h3>How to find the minimum value of a function?</h3>
The minimum value of a function is the lowest vertex value of the
function.
The given graph description, is the graph of the following function;
f(t) = 0.5·sin(t) - 5.5
The minimum value is given at the location where, sin(t) = -1, which gives;
f(t) = 0.5 × (-1) - 5.5 = -6
The minimum value of the function is therefore;
Learn more about the graphs of functions here:
brainly.com/question/26254100
This problem deals the rate of change.
For the formula of the area of a circle, we differentiate both sides with respect to time t.
(A = πr^2) d/dt
dA/dt = 2πr (dr/dt)
Since we don't know yet the radius r, the area of a circle is given.
A = πr^2
r^2 = A/π = 4π/π
r^2 = 4
r = 2 cm
Therefore, the rate of the radius is
dA/dt = 2πr (dr/dt)
dr/dt = (dA/dt)/(2πr)
dr/dt = π/(2π*2)
dr/dt = 0.25 cm/min
Hope this helps.