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kompoz [17]
3 years ago
14

A58 B67 C72 D62 Please help me

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0
A triangle has 180 degrees.
56+62+x=180
118+x=180
x=62
The answer is D 62
Hope this helped. Please give brainliest if it did!
You might be interested in
If r(x) = 3x - 1 and s(x) = 2x , which expression is equivalent to (r/s) (6)
VikaD [51]

Step-by-step explanation:

(r/s)(x)=<u>3x-1</u>

2x

(r/s)(6)=18-1/12

=17/12

8 0
3 years ago
The height, h, in meters above ground, of a projectile at any time, t, in seconds, after the launch is defined by the
Jlenok [28]

Answer:

the projectile reached a maximum height of 27.6 meters in 2.4 seconds and it took 5.0 seconds for it to hit the ground

Step-by-step explanation:

to find the vertex you can find the axis of symmetry first

that equation is -b/2a

-19/-8 = 2.375

then you take this and plug it in

-4(2.375)^2 + 19*2.375 + 5

that gives you 27.5625

then you have to find when it hits the ground

you can factor to find this out

-4t^2 + 19t + 5

4t^2 - 19t - 5

4t^2 + t - 20t - 5

t(4t + 1) -5(4t +1)

(t - 5)(4t + 1)

t = {5, -1/4}

we can only take positive time so it took 5 seconds

the answer is the second one

5 0
2 years ago
One meter equals 100 centimeters five meters equals how many centimeteres
Lapatulllka [165]
1 meter = 100 cm
while 5 meters = 500 cm
7 0
3 years ago
Find the midpoint of the segment with the following endpoints. (3, 2) and (9, 6)
myrzilka [38]

Answer:

The answer is

<h2>( 6 , 4 )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x_1 + x_2}{2} , \:  \frac{y_1 + y_2}{2} )\\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3, 2) and (9, 6)

The midpoint is

M = ( \frac{3 + 9}{2}  \:  , \:  \frac{2 + 6}{2} ) \\  = ( \frac{12}{2}  \: , \:  \frac{8}{2} )

We have the final answer as

<h3>( 6 , 4 )</h3>

Hope this helps you

5 0
4 years ago
Find the zeros of the function (x+3)^2(x-5)^6 and state the multiplicity
nikklg [1K]
Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
3 0
4 years ago
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