Answer:
1). 0.903547
2). 0.275617
Step-by-step explanation:
It is given :
K people in a party with the following :
i). k = 5 with the probability of 
ii). k = 10 with the probability of 
iii). k = 10 with the probability 
So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)
= 1 - P (choosing the n different months out of 365 days) = 
1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)
= 
= 
= 0.903547
2).P( k = 10|at least 2 share their birthday in same month)
=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)
= 
= 0.0.275617
The way that you would do this is by taking

out of the binomial, or as I like to think about it, 'un-distributing'. :p

out of

, you end up with

.
When you take

out of

, you get

.
Put it together, and the solution is

-

.
Hope I helped!!
Answer: 327 1/3
Step-by-step explanation:
Ashibeddaba
Step-by-step explanation:
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