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3 years ago

Find the measure of side NO. Figures are not drawn to scale.

Mathematics

1 answer:

miskamm [114]3 years ago

7 0

Its being dilated by 3 therefore your answer is 9.9

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Evaluate a^2b^2? when a = 5 and b = 3.

kvasek [131]

Answer:

$D) 7$

Step-by-step explanation:

$a^{2} -2b^{2}$

$a=5$

$b=3$

$\left(5\right)^2-2\left(3\right)^2$

Calculate 5 to the power of 2 and get 25:-

$25-2\times 3^{2}$

Calculate 3 to the power of 2 to get 9 and then multiply 2 and 9 to get 18:-

$25-18$

$=7$

<u>OAmalOHopeO</u>

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2 years ago

11) It's perimeter

natta225 [31]

2.8 m = .0028 km
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3 years ago

SimplIfy [(-49)÷7]÷(-7)]

Marysya12 [62]

Answer:

I think the answer is 1

Step-by-step explanation:

-49÷7=-7

-7÷-7=1

4 0

3 years ago

Richard had his car repaired at a body shop.

Alisiya [41]

Answer:

2 hours

Step-by-step explanation:

308-100=208

208÷52=2

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3 years ago

Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8

goblinko [34]

$\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y = \frac{17}{14} } \atop {x+7y=8}} \right.$

To solve this system by substitution, first isolate x in the second equation.

$x+7y=8$
$x+7y-7y=8-7y$
$x=8-7y$

Now, plug this expression ( $8-7y$ ) for x in the top equation to solve for y.

$\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}$
$3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}$
$72-63y+8y=17$
$72-55y=17$
$-55y=17-72$
$-55y=-55$
$y=1$

Now that you have y, plug it into the second equation and solve for x.

$x+7y=8$
$x+7(1)=8$
$x+7=8$
$x=1$

Last step is to plug your x- and y-values in to both equations to check your work.

$\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}$

$\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ; \frac{1}{3} * \frac{8}{8} = \frac{8}{24}$

$\frac{9}{24} + \frac{8}{24} = \frac{17}{24}$ <--True

$1+7(1)=8$
$1+7=8$ <--True

Answer:
$x=1 \\ y=1$

5 0

3 years ago

Find the measure of side NO. Figures are not drawn to scale.​

Find the measure of side NO. Figures are not drawn to scale.