<span>se
sen x = 3/5 eleva ao quadrado ambos os lados
sen² x = (3/5)²
Tem que partir da relação fundamental
sen²x + cos²x = 1
(3/5)² + cos² x = 1
cos² x = 1 - (3/5)² = 16/25
cos x = V(16/25 = 4/5
b ) tg x = sen x / cos x = 3/5 / 4/5 = 3/5 * 5/4 = 3/4
c) cotg x = cosx / sen x = 1 / tgx = 1/ (3/4 = 4/3
d) sec x = 1/ cos x = 1 / 4/5 = 5/4
e) cossec x = 1 / sen x = 1/ 3/5 = 5/3
se gostou , avalie
edson</span>edson <span>· 9 anos atrás</span>
Answer:
a common factor would be 5m^4n^3 or 15m^2n^2
Step-by-step explanation:
not sure what terms they want you to choose from but anything that starts with a number (5,10,15,) and "m" would any number 5 would go into
Answer:
A. >
Step-by-step explanation:
To compare two fractions, first find the common denominator (least common multiple of the denominators).
The least common multiple of 5 and 12 is 60.
7/12 = 35/60
1/5 = 12/60
Now that they have the same denominator, it's easy to compare.
35/60 > 12/60
no seeeeeeeeeeeeeee
Step-by-step explanation:
lol