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2 years ago

What is the answer of this question ?

Mathematics

1 answer:

fgiga [73]2 years ago

6 0

Answer:

the answer is B

Step-by-step explanation:

hoped I helped:)

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You weld two piece's of steel together. The toral thickness is 33/64 inch. If one piece of steel is 9/32 inch thick, how thick t

Anon25 [30]

Subtract the thickness of the known piece from the total thickness.

Because they have different denominators rewrite them to have the same.

9/32 x 2 = 18/64

Now you have 33/64 - 18/64 = 15/64

The other piece is 15/64 inch thick.

4 0

2 years ago

I need help lol. please give me an explaination as well ty <3

Feliz [49]

You need to write it out such as number 8 would be 10x10x10x10 so for every number on top you multiply the number by itself

3 0

2 years ago

The amount, A, in milligrams, of radioactive material remaining in a container can be modeled by the exponential function A(t) =

lisov135 [29]

Answer: 4 years

Step-by-step explanation:

A(0) has to be amount at start. Assume that's 5mg

Then A(t) = 5×(0.5)^(0.25t) = 5×2^(-t/4),

(also known as 5 exp(-λ t) with λ = ln(2)/4, incidentally).

We need to such that A(t) = 2.5mg, or 2^(-t/4) is 1/2, which happens when -t/4 is -1, or t is 4.

4 0

3 years ago

The sum of two numbers is 0. Twice the smaller number subtracted from 3 times the larger number is 10. Let x represent the large

Bezzdna [24]

Answer:

x+y=0 and 3x-2y=10

Step-by-step explanation

Let the numbers be x and y.

The sum of the two numbers is 0

$\implies \: x + y =0$

Letting the smaller number be y and the

larger number be x:

twice the smaller number

$\implies \: 2y$

Also, 3 times the larger number

$\implies \: 3x$

Now ,twice the smaller number subtracted from 3 times the larger number is 10.

$\implies \: 3x - 2y = 10$

Therefore the equations are

$x + y =0$

and

$3x - 2y =10$

6 0

3 years ago

In ΔJKL, l = 860 inches, j = 920 inches and ∠K=126°. Find ∠L, to the nearest degree.

fomenos

Answer:

Step-by-step explanation:

JKL= ABC, jkl=abc

1.) use law of sines to find k.

$c^{2} =a^{2} +b^{2} -2abCosC$

$c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515$

2.) use law of cosines to find L

$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

plug in for b and c: $\frac{860}{sinB} =\frac{1586.225515}{sin126}$

cross multiply: $\frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}$

$sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\$

L=26

5 0

3 years ago