F(x) = (1/x) + ln x
At the extreme values, f'(x) = 0
f'(x) = -1/x^2 + 1/x = 0
(x - 1)/x^2 = 0
x - 1 = 0
x = 1
f(1) = 1/1 + ln 1 = 1
Therefore, the extereme value is 1 and occurs at x = 1.
Y = mx + b
y = -3(x) + b
4 = -3(-1) + b
4 = 3 + b
b = 4 - 3
b = 1
y = -3x + 1.
Answer:
Step-by-step explanation:
f(x) = -1/3x + 1:
<span><span>4,000,000 </span><span>+400,000 </span><span>+0 </span><span>+8,000 </span><span>+700 </span><span>+30 </span><span>+0</span></span>
D. 2.888 in plato the right answer
