The measures of two sides of a triangle are 3x + 4y and 5x - y. If the perimeter is 10x + 5y, find the measure of the third side.
<span>Let measure of the 3rd side be 'b'. </span>
<span>Substitute the values of length of the two sides and perimeter in equation and solve for b. </span>
<span>So, 10x + 5y = 3x + 4y + 5x - y + b..........[Substitute the values] </span>
<span>10x + 5y = 8x + 3y + b </span>
<span>(10x + 5y) - (8x + 3y) = b </span>
<span>10x + 5y - 8x - 3y = b </span>
<span>10x - 8x + 5y - 3y = b </span>
<span>2x + 2y = b </span>
<span>So, the measure of the third side is 2x + 2y. </span>
5) 870 is 10 more than 860
6) 782 is 100 less than 882
7) 129 is 100 more than 29
8) 333 is 100 less than 433
W=80 because 30 is subtracted from w which makes
fifty 80 - 30=50
You can also check the answer by adding 30 and 50 which makes 80
Answer: For Mrs. Bhan, she pay 9.75 each visit for ten time so 10 ÷ 97.50
I don’t know how to answer for Mr. Stewart but I answer Mrs. Bhan. Hope this helps!
