A. f(x)=ln(x+4)-5
If it shifts to the left side then in braces put a (+) sign and if it shifts to the right then in braces put a (-) sign. If it goes up it’s positive and if it goes down it’s negative
Answer and explanation:
Statement - If the difference of two numbers is even then so is their sum.
Let the two even numbers be '2m' and '2n' with m and n are integers.
The difference of two number is
Now, The sum of the numbers is
Let 
where k is an integer
Then, 
which is also an even number as 2 is multiplied with it.
So, If the difference of two numbers is even then so is their sum.
For example -
Let two even number 2 and 4.
The difference is 
, 2 is even.
The sum is 
, 6 is even.
The radius of your cone is half of 18 units = 9 units.
The volume of any cone is <span><span>V = (1/3) · (pi) · (radius)² · (height) </span>
</span>
-- Take that formula for the volume of any cone.
-- Write '8' in place of 'height'.
-- Write '9' in place of 'radius'.
-- Write '3.142' in place of 'pi'.
-- Complete the arithmetic.
-- Bada-bing, you've got the volume.
Answer:
Volume of square based pyramid = 116.62 cm³
Step-by-step explanation:
Given:
Perimeter of square base = 16.9 cm
Height of pyramid = 19.6 cm
Find:
Volume of square based pyramid
Computation:
Perimeter of square base = 16.9 cm
4[Side] = 16.9
Side = 4.225 cm
Area of square = Side x Side
Area of square = 4.225 x 4.225
Area of square = 17.85 cm²
Volume of square based pyramid = [Area of square][Height of pyramid] / 3
Volume of square based pyramid = [17.85][19.6] / 3
Volume of square based pyramid = 349.86 /3
Volume of square based pyramid = 116.62 cm³
Answer:
The solutions are a₁ = -4/19 i, a₂ = 4/19 i and a₃ = -1/4
Step-by-step explanation:
Given the equation 76a³+19a²+16a=-4, for us to solve the equation, we need to find all the factors of the polynomial function. Since the highest degree of the polynomial is 3, the polynomial will have 3 roots.
The equation can also be written as (76a³+19a²)+(16a+4) = 0
On factorizing out the common terms from each parenthesis, we will have;
19a²(4a+1)+4(4a+1) = 0
(19a²+4)(4a+1) = 0
19a²+4 = 0 and 4a+1 = 0
From the first equation;
19a²+4 = 0
19a² = -4
a² = -4/19
a = ±√-4/19
a₁ = -4/19 i, a₂ = 4/19 i (√-1 = i)
From the second equation 4a+1 = 0
4a = -1
a₃ = -1/4
