<u>Answer-</u>
<em>The interval where the function is diffrentiable is </em>
![[-\infty,1)\ \bigcup\ (1,\infty]](https://tex.z-dn.net/?f=%5B-%5Cinfty%2C1%29%5C%20%5Cbigcup%5C%20%281%2C%5Cinfty%5D)
<u>Solution-</u>
The given expression is,

The function will be differentiable where it is continuous and it will not be differentiable, where the function is not continuous.
The function continuous everywhere except at x = 1, because

at x = 1, its limit does not exist.
Therefore, apart from x=1, this function is differentiable everywhere. The interval will be
![[-\infty,1)\ \bigcup\ (1,\infty]](https://tex.z-dn.net/?f=%5B-%5Cinfty%2C1%29%5C%20%5Cbigcup%5C%20%281%2C%5Cinfty%5D)
Answer:

Step-by-step explanation:




<h3>Hope it is helpful....</h3>
Answer: I don't see what your talking about here, so I can't help you.
Step-by-step explanation:
<span>What is the value of c?
5x2 - 3y2 - 20x + 6y + 2 = 0
Select one:
a. 2
b. 4
c. √4
d. √8
This was an older question and someone said the answer was D and I got it right.</span>
14.5% = 0.145 = 145/1000
14.5 = 14500/1000
So 14.5% is a hundredth the size of 14.5, so they are not equal and the friend is incorrect.