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Evgesh-ka [11]
4 years ago
7

Which undefined geometric term is described as a location on a coordinated plane that designated by an ordered pair,(x,y)?

Mathematics
2 answers:
boyakko [2]4 years ago
5 0
<h2>Answer:</h2>

The undefined geometric term is described as a location on a coordinated plane that designated by an ordered pair,(x,y) is:

                                 Point

<h2>Step-by-step explanation:</h2>

There are three undefined terms in geometry--

1) Point

2) Line

3) Plane

<u>Point--</u>

A point is just a location on a coordinate grid.

It has no dimension and in represented by (x,y)

<u>Line--</u>

A line is a line of collection of set of points and is extended infinitely in both the directions.

The x-axis may also be considered as a line as it satisfies the equation y=0

The general equation of line in coordinate plane is:

       ax+by=c

<u>Plane--</u>

A plane is a two dimensional surface which extends infinitely.

               Hence, the answer is:

                    Point

zepelin [54]4 years ago
4 0

undefined slope = (16,3), ( 16, -80)


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Nina rented a bicycle while she was on vacation she paid a flat rental fee of $75.00
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All athletes at the Olympic Games (OG) are tested for performance-enhancing steroid drug use. The basic Anabolic Steroid Test (A
Semenov [28]

Answer:

a ) the probability of using steroids and having a negative test is 0.5%

b) The probability of testing positive is 6.4%

c) The probability of not using steroids, given that the test is negative is 99.47%

d) No, they are not statistically indepent.

e) The probability that the athlete will either use steroids or test positive is 6.9%

Step-by-step explanation:

Let A be the event that the test result is positive and B the event that the athlete uses Steroids. We are given the following

P(A|B) = 90%, P(A|B^c) = 2%, P(B) = 5%

From which we deduce that

P(A^c|B) = 10%, P(B^c) = 95%

a) We are asked for the probability P(A^c\cap B). REcall the conditional probability formula that, given two events C,D the conditional probability P(C|D) = \frac{P(C\cap D)}{P(D)}. Then we have that

P(A^c\cap B) = P(A^c|B)P(B) = 10\% \cdot 5\%=0.5\%.

b) We are asked for the probability P(A). We can use the fact that given two mutually exclusive events(that is, whose intersection is empty) A,B the probability P(C) of an event is given by P(C) = P(C|A)P(A)+P(C|B)P(B). Then

P(A) = P(A|B)P(B)+P(A|B^c)P(B^c) = 90\%\cdot5\% + 2\% \cdot 95% = 6.4\%

c) We are asked for the probability P(B^c|A^c). Recall that P(A|B) = \frac{P(B|A)P(A)}{P(B)}. Then

P(B^c|A^c) = \frac{P(A^c|B^c)P(B^c)}{P(A^c)}= \frac{P(A^c|B^c)P(B^c)}{1-P(A)}= \frac{(1-P(A|B^c))P(B^c)}{1-P(A)}=\frac{98\%\cdot 95\%}{1-6.4\%}= 99.47\%

d) We say that two events A,B are statistically indepent if P(A|B) = P(A). Note that from point B the probability of testing negative is 1- 6.4% = 93.6%. Since 93.6% is different from 99.47% this means that testing positive and using steroids are not statistically independent.

e) We are asked for the probability P(A\cup B). We use the following

P(A\cupB) = P(A)+P(B)-P(A\cap B) = P(A) +P(B)-P(A|B)P(B) = 6.4\%+5\%-90\%\cdot 5\%=6.9\%

4 0
4 years ago
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