Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
<h3>The answer is </h3><h3 /><h3>1125 Kg</h3>
Step-by-step explanation:
To find the mass in kg we must first convert the density from g/cm³ to kg/m³
That's 7.5 g/cm³ = 7500kg/m³
Density = mass / volume
Volume of block = 1.5 × 0.4 × 0.25
= 0.15m³
mass = Density × volume
= 7500 × 0.15
<h3>= 1125 Kg</h3>
Hope this helps you
Answer: 130.666
Step-by-step explanation:
Y = -3/4x + 6
you write in the y=mx+c form!
m= the slope
c = the y-intercept. (it is the second number of the coordinates)
Answer:
0.0273
Step-by-step explanation:
np n
10 100
9 100
11 100
7 100
3 100
12 100
8 100
4 100
6 100
11 100
pbar=sumnp/sumn
pbar=10+9+11+7+3+12+8+4+6+11/10+10+10+10+10+10+10+10+10+10
pbar=81/1000
pbar=0.081
nbar=sumn/k=1000/10=100




Standard deviation for p-chart=0.0273