3 years ago

PLS HELP

Mathematics

1 answer:

sleet_krkn [62]3 years ago

8 0

Answer: the 3rd one

Step-by-step explanation:

You might be interested in

Find the center and radius of this circle.<br> x2 + y2 − 40x − 24y + 15 = 0

Julli [10]

ANSWER

Center: (20,12)

Radius:23

EXPLANATION

The given circle has equation:

${x}^{2} + {y}^{2} - 40x - 24y + 15 = 0$

We complete the square as follows:

${x}^{2} - 40x + {y}^{2} - 24y = - 15$

${x}^{2} - 40x + {( - 20)}^{2} + {y}^{2} - 24y + {( - 12)}^{2} = - 15+ {( - 20)}^{2}+ {( - 12)}^{2}$

${(x - 20)}^{2} + {(y - 12)}^{2} = - 15+ 400+ 144$

${(x - 20)}^{2} + {(y - 12)}^{2} = 529$

${(x - 20)}^{2} + {(y - 12)}^{2} = {23}^{2}$

Comparing this equation to:

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

We have

$(h,k)=(20,12)$

representing the center and

$r = 23$

being the radius.

5 0

3 years ago

Write the equation of the line where slope is 12 and y-intercept is -1.

il63 [147K]

The answer is y=12x-1

7 0

3 years ago

Evaluate f(x) = –x2 – 4 for x = –3.

melisa1 [442]

The answer to your problem is 2

6 0

4 years ago

Read 2 more answers

What does it mean for a differential equation to be autonomous?

andrew11 [14]

The term "autonomous" refers to an ordinary differential equation that relates the derivatives of the dependent variable as a function *only* of the dependent variable. In other words, the ODE doesn't explicitly depend on the independent variable.

Examples:

$y'=y^2-1$ is autonomous

$y'=y^2-1+x$ is *not* autonomous

7 0

3 years ago

In the equation $\frac{1}{j} + \frac{1}{k} = \frac{1}{3}$, both $j$ and $k$ are positive integers. What is the sum of all possib

Darina [25.2K]

Answer:

ayo ion get the equation. type up it again?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers