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spayn [35]
3 years ago
6

PLS HELP

Mathematics
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer: the 3rd one

Step-by-step explanation:

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Carly has 168 markers,
Margarita [4]

Answer:

2016 markers

Step-by-step explanation:

168

x 12

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2016

5 0
3 years ago
Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
2 years ago
According to a survery 52% of the residents of a city oppose a downtown casino. Of these 52% about 5 out of 10 strongly oppose t
nignag [31]
<span>I need to satert by stating the questions clearly. Question A: What is the probability that a radomly selected resident opposes the casino and strongly opposes the casino? This is the joint probability of being opposed and being strongly opposes which is calculated as the product of both: 52/100 * 5/10 = 26/100 = 0.26. Question B. What tis the probability that a radomly selected resident opposes the casino and does not strongly oppose the casino. Again it is a joint probability, the product of being opposed and not being strongly opposed: 52/100 * 5/10 = 26/100 = 0.26. The are the same because the the half of the 52% oppose strongly and the other half does not. </span>
8 0
3 years ago
What is 9/3 as a fraction?
koban [17]
9/3 is already made a fraction.

Why?

Because it is not a whole numer.

Well, this improper fraction can be simplified.

<u>9 </u>  ÷ 3<u>
</u>3    ÷ 3

= 1.
<u />
4 0
3 years ago
Read 2 more answers
Find the jacobian of the transformation. x = 6v + 6w2, y = 8w + 8u2, z = 2u + 2v2
V125BC [204]
The answer for that problem is z =12+6
4 0
3 years ago
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