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Ostrovityanka [42]
3 years ago
14

Find the values of < and y. (8x + 7) 5yº (7y -- 34) = (2x - 4)^

Mathematics
2 answers:
Lilit [14]3 years ago
6 0

Answer:

x = 11

y = 17

Step-by-step explanation:

We know that opposite angles (or vertical angles) are equal.

So

8x + 7 = 9x - 4

Subtract 8x from both sides of the equation

8x - 8x + 7 = 9x - 8x - 4

7 = x - 4

Add 4 to both sides of the equation

7 + 4 = x - 4 + 4

11 = x

Looking at the other 2 angles,

5y = 7y - 34

Subtract 7 y from both sides of the equation

5y - 7y = 7y - 7y - 34

-2y = -34

Divide both sides by -2

-2y/-2 = -34/-2

y = 17

Virty [35]3 years ago
5 0

Answer:

Step-by-step explanation:

Vertically opposite angles are equal.

8x + 7     = 9x - 4          {Add 4 to both sides}

8x + 7 + 4 = 9x

    8x  + 11  = 9x           {Subtract 8x from both sides}

            11 = 9x - 8x

x = 11

7y - 34 = 5y        {Add 34 to both sides}

        7y = 5y + 34          {Subtract 5y form both sides}

  7y - 5y = 34

         2y = 34                {Divide both sides by 2

            y = 34/2

y =17

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Dividing the polynomial P(x) by x-6 yields a quotient by Q(x) and a remainder of 5.
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Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.

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