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Likurg_2 [28]
3 years ago
9

Using the following data set:

Mathematics
2 answers:
Luba_88 [7]3 years ago
3 0

dfghjdfghj

bjkbvjfkbvjbvf

Delvig [45]3 years ago
3 0

Answer:

should be like 47 but I'm not 100% sure

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One angle is twice its supplement increased by 36°. Find the measures of the two supplementary angles.
agasfer [191]

Answer:

48 and 132 degrees

Step-by-step explanation:

supplement=s

one angle=2s+36

2s+36+s=180

3s+36=180

3s=144

s=48

2(48)+36=132

Therefore, 48 and 132 degrees

I hope this helped and have a good rest of your day!

8 0
3 years ago
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
15. Write<br> 7x1 + 3 x (1/10) +<br> 4 x (1/100)<br> in standard form.
MA_775_DIABLO [31]

Answer:

7.34

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Sqrt(x+7) -1=x<br><br><br> yo what
MAVERICK [17]

Hi

\sqrt{(x+7)   -1 = X

Let's square the whole thing  

so we have :    x+7 +1 = x²

                         x² +x+7 +1 = 0

                         x²+x+8 = 0

       

no easy way to see a common factor so, let 's resolve by using discriminate.  

Δ = 1-4*1*8

Δ = 1 -32

Δ = -31

as Δ  ≤ 0 , there is no Real answer to your equation  

however , if you need we can find imaginary solutions. Just ask in commentaries

4 0
3 years ago
The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni
charle [14.2K]

Answer:

(a)77.4bpm

(b)Mean of Sample 1 = 70.3 beats per minute.  

Mean pulse of sample 2 = 70 beats per minute.

(c)

  • The mean pulse rate of sample 1 underestimates the population mean.
  • The mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

(a)Population mean pulse.

The pulse of the nine students which represent the population are:

  • Perpectual Bempah      64
  • Megan Brooks               77
  • Jeff Honeycutt               89
  • Clarice Jefferson           69
  • Crystal Kurtenbach       89
  • Janette Lantka              65
  • Kevin McCarthy             88
  • Tammy Ohm                  69
  • Kathy Wojdya                 87

\text{Population Mean} =\dfrac{64+77+89+69+89+65+88+69+87}{9} \\=\dfrac{697}{9} \\\\=77.44

The population mean pulse is approximately 77.4 beats per minute.

(b)Sample 1: {Janette,Clarice,Megan}

  • Janette: 65bpm
  • Clarice: 69bpm
  • Megan: 77bpm

Mean of Sample 1

\text{Sample 1 Mean} =\dfrac{65+69+77}{3} \\=\dfrac{211}{3} \\\\=70.3

Sample 2: {Janette,Clarice,Megan}

  • Perpetual: 64bpm
  • Clarice: 69bpm
  • Megan: 77bpm

Mean of Sample 2

\text{Sample 2 Mean} =\dfrac{64+69+77}{3} \\=\dfrac{210}{3} \\\\=70

The mean pulse of sample 1 is approximately 70.3 beats per minute.  

The mean pulse of sample 2 is approximately 70 beats per minute.

(c)

  • The mean pulse rate of sample 1 underestimates the population mean.
  • The mean pulse rate of sample 2 underestimates the population mean.
7 0
3 years ago
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