Answer:
48 and 132 degrees
Step-by-step explanation:
supplement=s
one angle=2s+36
2s+36+s=180
3s+36=180
3s=144
s=48
2(48)+36=132
Therefore, 48 and 132 degrees
I hope this helped and have a good rest of your day!
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
Answer:
7.34
Step-by-step explanation:
Hi
-1 = X
Let's square the whole thing
so we have : x+7 +1 = x²
x² +x+7 +1 = 0
x²+x+8 = 0
no easy way to see a common factor so, let 's resolve by using discriminate.
Δ = 1-4*1*8
Δ = 1 -32
Δ = -31
as Δ ≤ 0 , there is no Real answer to your equation
however , if you need we can find imaginary solutions. Just ask in commentaries
Answer:
(a)77.4bpm
(b)Mean of Sample 1 = 70.3 beats per minute.
Mean pulse of sample 2 = 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.
Step-by-step explanation:
(a)Population mean pulse.
The pulse of the nine students which represent the population are:
- Perpectual Bempah 64
- Megan Brooks 77
- Jeff Honeycutt 89
- Clarice Jefferson 69
- Crystal Kurtenbach 89
- Janette Lantka 65
- Kevin McCarthy 88
- Tammy Ohm 69
- Kathy Wojdya 87

The population mean pulse is approximately 77.4 beats per minute.
(b)Sample 1: {Janette,Clarice,Megan}
- Janette: 65bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 1

Sample 2: {Janette,Clarice,Megan}
- Perpetual: 64bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 2

The mean pulse of sample 1 is approximately 70.3 beats per minute.
The mean pulse of sample 2 is approximately 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.