The answer is for this expression 4.85
The mode is a number that is repeated the most, so if there is 3 numbers, the "mode number" has to be repeated twice or three times.
A) since 1 is the mode, two of the numbers are 1, the last number is
15 -1 -1 = 13 <em> </em><em> the three numbers are 1, 1, and 13</em><em />.
B) since 5 is the mode, two of the numbers are 5, the last number is
11 -5 -5 = 1 <em> </em><em> the three numbers are 5, 5, and 1</em><em />.
Range is when you subtract the smallest number to the biggest number, so 5-1=4 <em>The answer is 4</em>
Answer:
The value of 
Step-by-step explanation:
We have given 
d=1.7
We have to find 
So,
from the formula

When n=14




Using the formula:

When n=26
![s_{26}=\frac{26}{2}[2(-18)+(26-1)(1.7)]](https://tex.z-dn.net/?f=s_%7B26%7D%3D%5Cfrac%7B26%7D%7B2%7D%5B2%28-18%29%2B%2826-1%29%281.7%29%5D)
On simplification we get:

Well, to cover the whole bridge, is 6/6, or 1 whole
so hmmm

X^3+3x^2-18x-3x^2-9x+54
————-
Final answer=
X^3-27x+54
I hope you understand my explanation and best of wishes!!