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2 years ago

6

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Answer- What is the square root of 64

2 answers:

AfilCa [17]2 years ago

5 0

The answer is 8 dude

zlopas [31]2 years ago

4 0

Answer:

The square root of 64 is 8

Thnx for the points and May God bless you ☺

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6. a semicircle has as its diameter the hypotenuse of a right triangle shown below. determine the area of the semicircle to the

jeyben [28]

Answer:

$A = 137.3cm^2$

Step-by-step explanation:

Given

See attachment

Required

The area of the semicircle

First, we calculate the hypotenuse (h) of the triangle

Considering only the triangle, we have:

$\cos(68) = \frac{7}{h}$ --- cosine formula

Make h the subject

$h = \frac{7}{\cos(68)}$

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$h = 18.7$

The area of the semicircle is then calculated as:

$A = \frac{\pi h^2}{8}$

This gives:

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Read 2 more answers

1) AU (C - B) =

torisob [31]

Answer:

$A \cup (C-B) = (A \cup C) \cap (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = A \cup (B \cup C)\\B^c \cap (A-C) = (B^c - C) \cap A\\(B \cap C) - A = (B-A)\cap C\\C-(A\cup B) = (C - A )\cap B\\A^c \cap (B \cap C) = ( A^c \cap B) \cap C$

Step-by-step explanation:

$A \cup (C-B) = A \cup (C \cap B^c) = (A \cup C) \cap (A \cup B^c)\\A \cup (B \cap C) = (A \cup B) \cap (A \cup C) \,\,\, \text{Here you use double inclusion.}\\A \cup B \cup C = (A \cup B ) \cup C = A \cup (B \cup C)\\B^c \cap (A-C) = B^c \cap (A \cap C^c) = (B^c \cap C^c) \cap A = (B^c - C) \cap A\\(B \cap C) - A = (B \cap C) \cap A^c = (B \cap C) \cap A^c = (B \cap A^c)\cap C = (B-A)\cap C\\C-(A\cup B) = C \cap (A\cup B)^c = C \cap (A^c \cap B^c ) = (C \cap A^c )\cap B^c = (C - A )\cap B\\$

$A^c \cap (B \cap C) = ( A^c \cap B) \cap C$

3 0

3 years ago